Construct box plot of the variable price. Identify whether there are outliers or not. Find the median price. Find the first quartile value. Find the third quartile value.

Question

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Answer 1

Question

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

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Answer 2

Question

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

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Answer 3

Question

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

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Answer 4

Question

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

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Answer 5

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

Answer 6

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

Answer 7

Chapter 4, Problem 37CE

a.

To determine

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Answer 8

a.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable price using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 1

Yes, there are 3 outliers in the dataset.

The median price is 3,733.

The first quartile value is 1,478.

The third quartile value is 6,141.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Price.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 3,733.

Hence, the median value is 3,733.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 1,478.

Hence, the third quartile value is 6,141.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 6,141.

Hence, the first quartile value is 1,478.

Answer 13

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

Answer 14

b.

To determine

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Answer 15

b.

Expert Solution

Answer to Problem 37CE

Output of box plot for the variable size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 2

Yes, there are 3 outliers in the dataset.

The median price is 0.84.

The first quartile value is 0.515.

The third quartile value is 1.12.

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation:

Step by step procedure to obtain boxplot using MINITAB software is given as,

Choose Graph > Boxplot.
In Graph variables enter the columns Size.
Click OK.

Outliers:

In the boxplot, the outlier is represented using asterisk. In the boxplot of data set there are 3 asterisks representing outliers. Hence, there are three outliers in the dataset.

Median:

The median is the middle value of the data set. In the boxplot, the line in middle of the box represents median of the dataset. The line corresponds to value 0.84.

Hence, the median value is 0.84.

First quartile:

The border line towards the left side of the box represents the value of first quartile. In this box plot, the line of the box on left side corresponds to the value approximately 0.515.

Hence, the third quartile value is 0.515.

Third quartile:

The border line towards the right side of the box represents the value of third quartile. In this box plot, the line of the box on right side corresponds to the value approximately 1.12.

Hence, the first quartile value is 1.12.

Answer 20

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

Answer 21

c.

To determine

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

Answer 22

c.

Expert Solution

Answer to Problem 37CE

Output of scatter diagram for variables price and size using MINITAB software is,

EBK STATISTICAL TECHNIQUES IN BUSINESS, Chapter 4, Problem 37CE , additional homework tip 3

Yes, there is association between the variables price and size.

The association is direct.

Yes, the first observation of both the price and size is large when compared to other observations.

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Calculation:

Step by step procedure to obtain scatter diagram using MINITAB software is given as,

Choose Graph > Scatterplot > select Simple.
In Y variable enter the column Price.
In X variable enter the column Size.
Click OK.

In the scatter diagram it can be observed that, the Price has increased as the Size increases indicating that the association between the variables.

Hence, there is association between the variables price and size

The relation is said to be direct if value of one variable increases due to effect of another variable. From the scatter diagram, the value of Price has increased as the Size increases indicating a direct or positive association.

Hence, the association is direct.

From the scatter diagram, it can be observed that one of the observations corresponding to the value of 5.03 carats for size and $44,312 for price is far from all the other observations. Hence, one point seems to be different from the others.

Answer 27

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

Answer 28

d.

To determine

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

Answer 29

d.

Expert Solution

Answer to Problem 37CE

The contingency table for the variables shape and cut grade is,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The most common cut grade is premium.

The most common shape is round.

The most common combination of cut grade and shape is premium and round.

Answer 30

d.

Expert Solution

Answer 31

d.

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Calculation:

Contingency table:

A table that is used for classifying observations based on the two identifiable characteristics is termed as contingency table. It is used for summarizing two variables.

The variable cut grade is classified into 5 different categories ‘average, good, ideal, premium, ultra ideal’. The variable shape is classified into 5 different categories ‘emerald, marquise, oval, princess, and round’.

Count the number of cut grades are average with shape of emerald. From the data, there is no combination of average cut grades with shape of emerald. Hence, the frequency is 0.

Similarly, count the frequency for each of the possible combination of cut grade and shape. Then calculate the totals for each column and row. The contingency table is obtained as below,

Shape	Cut Grade
Shape	Average	Good	Ideal	Premium	Ultra Ideal	Total
Emerald	0	0	1	0	0	1
Marquise	0	2	0	1	0	3
Oval	0	0	0	1	0	1
Princess	1	0	2	2	0	5
Round	1	3	3	13	3	23
Total	2	5	6	17	3	33

The cut grade ‘Premium’ has a total of 17, which is large when compared to other cut grades. This shows that, the most common cut grade of diamonds is ‘Premium.

Hence, the most common cut grade is premium.

The shape ‘Round’ has a total of 23, which is large when compared to other shapes. This shows that, the most common shape of diamonds is ‘Round’.

Hence, the most common shape is round.

The combination of cut grade ‘Premium’ and shape ‘Round’ has a total of 13, which is large when compared to other combinations. This shows that, the most common combination of diamonds is cut grade ‘Premium’ and shape ‘Round’.

Hence, the most common combination of cut grade and shape is premium and round.

Answer 34

Ch. 4 - Prob. 1.1SR Ch. 4 - Prob. 1.2SR Ch. 4 - Describe the differences between a histogram and a...Ch. 4 - Prob. 2E Ch. 4 - Consider the following chart. a. What is this...Ch. 4 - The following chart reports the number of cell...Ch. 4 - Prob. 5E Ch. 4 - Prob. 6E Ch. 4 - Prob. 7E Ch. 4 - Prob. 8E

Construct box plot of the variable price. Identify whether there are outliers or not. Find the median price. Find the first quartile value. Find the third quartile value.

Solution Summary: The author explains how to construct a box plot of the variable price, identifying whether there are outliers or not.

Concept explainers

Videos

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Answer to Problem 37CE

Explanation of Solution

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Answer to Problem 37CE

Explanation of Solution

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

Answer to Problem 37CE

Explanation of Solution

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.

Answer to Problem 37CE

Explanation of Solution

Want to see more full solutions like this?

Chapter 4 Solutions

Construct box plot of the variable price. Identify whether there are outliers or not. Find the median price. Find the first quartile value. Find the third quartile value.

Solution Summary: The author explains how to construct a box plot of the variable price, identifying whether there are outliers or not.

Concept explainers

Videos

Construct box plot of the variable price. Identify whether there are outliers or not. Find the median price. Find the first quartile value. Find the third quartile value.

Answer to Problem 37CE

Explanation of Solution

Construct box plot of the variable size. Identify whether there are outliers or not. Find the median price. Find the first quartile value. Find the third quartile value.

Answer to Problem 37CE

Explanation of Solution

Construct scatter diagram for variables price and size. Identify whether there is association between the two variables or not. Identify whether association is direct or indirect. Identify whether any point seems to be different from the others.

Answer to Problem 37CE

Explanation of Solution

Construct a contingency table for the variables shape and cut grade. Find the most common cut grade. Find the most common shape. Find the most common combination of cut grade and shape.

Answer to Problem 37CE

Explanation of Solution

Want to see more full solutions like this?

Chapter 4 Solutions

Construct box plot of the variable price.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Construct box plot of the variable size.

Identify whether there are outliers or not.

Find the median price.

Find the first quartile value.

Find the third quartile value.

Construct scatter diagram for variables price and size.

Identify whether there is association between the two variables or not.

Identify whether association is direct or indirect.

Identify whether any point seems to be different from the others.

Construct a contingency table for the variables shape and cut grade.

Find the most common cut grade.

Find the most common shape.

Find the most common combination of cut grade and shape.