21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 35QP
To determine
The time takes for Newton’s cannonball to complete one orbit around Earth.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The International Space Station is in a 260-mile-high orbit.
What is the station's orbital speed? The radius of Earth is 6.37×10^6m, its mass is 5.98×10^24kg.
What is the station's orbital period?
The International Space Station is in a 250-mile-high orbit.
What is the station's orbital speed? The radius of Earth is 6.37×10^6 m, its mass is 5.98×10^24 kg.
What is the station's orbital period?
A satellite has an orbital radius of 100km above the earth's surface. Earths mass= 5.97x10^24kg. Earths radius=6.38x10^6. What is the speed of the satellite? How many minutes does it take the satellite to complete one orbit?
Chapter 4 Solutions
21st Century Astronomy
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The astronaut orbiting the Earth in Figure P3.27 is preparing to dock with a Westar VI satellite. The satellite is in a circular orbit 600 km above the Earth’s surface, where the free-fall acceleration is 8.21 m/s2. Take the radius of the Earth as 6 400 km. Determine the speed of the satellite and the time interval required to complete one orbit around the Earth, which is the period of the satellite. Figure P3.27arrow_forwardCalculate the effective gravitational field vector g at Earths surface at the poles and the equator. Take account of the difference in the equatorial (6378 km) and polar (6357 km) radius as well as the centrifugal force. How well does the result agree with the difference calculated with the result g = 9.780356[1 + 0.0052885 sin 2 0.0000059 sin2(2)]m/s2 where is the latitude?arrow_forwardLet gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forward
- Model the Moons orbit around the Earth as an ellipse with the Earth at one focus. The Moons farthest distance (apogee) from the center of the Earth is rA = 4.05 108 m, and its closest distance (perigee) is rP = 3.63 108 m. a. Calculate the semimajor axis of the Moons orbit. b. How far is the Earth from the center of the Moons elliptical orbit? c. Use a scale such as 1 cm 108 m to sketch the EarthMoon system at apogee and at perigee and the Moons orbit. (The semiminor axis of the Moons orbit is roughly b = 3.84 108 m.)arrow_forwardThe International Space Station (ISS) completes one orbit of Earth in 92 minutes. What is the radius of the orbit in kilometers (km)? You may assume the orbit is circular. The mass of the ISS is 420 kg, and the mass of the Earth is 6.0×10246.0×1024kg. Newton’s gravitational constant is 6.7×10−11N⋅m2kg26.7×10−11kg2N⋅m2.arrow_forwardScientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)Which of the following quantities would change the radius the satellite needs to orbit at? a.)the mass of the satellite b.)the mass of the planet c.)the speed of the satellite 2.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?arrow_forward
- A satellite orbits a planet in a circular orbit at an altitude (distance above the surface) of 1000km. The radius of the planet is 8000 km. The mass of the planet is 8 x 10^24 kg. What is the orbital speed? Your answer The gravitational force between a planet and its moon is óx10^16 N. For another moon orbiting the same planet with twice the orbital radius and 3 times the 5.arrow_forwardThe International Space Station is in a 210-mile-high orbit. What is the station's orbital speed? The radius of Earth is 6.37×10^6 m, its mass is 5.98×10^24kg. Express your answer with the appropriate units. What is the station's orbital period? Express your answer in minutes.arrow_forwardThe Magellan orbiter orbits Venus with a period of 3.26 hours. How far (in km) above the surface of the planet is it? (The mass of Venus is 4.87 ✕ 1024 kg, and the radius of Venus is 6.05 ✕ 103 km.)arrow_forward
- The Magellan orbiter orbits Venus with a period of 3.26 hours. How far (in km) above the surface of the planet is it? (The mass of Venus is 4.87 ✕ 1024 kg, and the radius of Venus is 6.05 ✕ 103 km.)arrow_forwardEarth’s mass is 5.98 x 1024 kg and it is located 150 million kilometers from the Sun. Calculate the mass of the Sun in [x1030 kg]. Find the speed, in [m/s], of a satellite orbiting the Earth 1000 km above its surface. Find the period, in [s], of a satellite orbiting the Earth 1000 km above its surface. (RE = 6.37 x 103 km & ME = 5.98 x 1024 kg)arrow_forwardA planet of mass m=3.05×10^24 kg orbits a star of mass M=3.85×1029 kg in a circular path. The radius of the orbit is R=7.65×10^7 km. What is the orbital period T planet of the planet in Earth days?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY