Engineering Fundamentals
6th Edition
ISBN: 9780357112144
Author: Saeed Moaveni
Publisher: MISC PUBS
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Textbook Question
Chapter 4, Problem 28P
Present Example 9.4 in Chapter 9 using the format discussed in Section 4.2. Divide the example problem into “Given,” “Find,” and “Solution” sections.
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Ex 11: Design inlet system for the road in figure below with
catchment area=86 m*239 m. C=0.8, i=100 mm/hr, Gutter data: y
max.=8cm, n=0.018, k=0.38, slope=%1, Z=25, %25 clogging,
(space=bar=2 cm). Inlet type used (consists of tow part curb and
Q grad inlet =0.6Qgutter max.
grade inlet) Q curb inlet =0.4Qgutter max.
0.8*100
3600*1000
Solution: (Qs) Total=CIA=
Qgutter (Max.)=k²√√s y8/3 = 0.38-
25
0.018
*(86*239)=0.457 m³/s
√0.01 0.088/3= 0.0627 m³/s
30 m
12 m
2mL
12 m
30 m
Residence
30 m
Streat
12 m
Bof
2 m
ㅈ
239 m
A2
A1
Chapter 4 Solutions
Engineering Fundamentals
Ch. 4.2 - Prob. 1BYGCh. 4.2 - Prob. 2BYGCh. 4.3 - Prob. 1BYGCh. 4.3 - Prob. 2BYGCh. 4.3 - Prob. 3BYGCh. 4.5 - Prob. 1BYGCh. 4.5 - Prob. 2BYGCh. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3P
Ch. 4 - Prob. 4PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Present Example 6.1 in Chapter 6 using the format...Ch. 4 - Present Example 6.3 in Chapter 6 using the format...Ch. 4 - Present Example 7.1 in Chapter 7 using the format...Ch. 4 - Present Example 7.4 in Chapter 7 using the format...Ch. 4 - Prob. 25PCh. 4 - Present Example 8.4 in Chapter 8 using the format...Ch. 4 - Prob. 27PCh. 4 - Present Example 9.4 in Chapter 9 using the format...Ch. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35P
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