Explanation The chemical reaction of Br − ion with the dilute solutions of AgNO 3 , BaCl 2 and Pb ( NO 3 ) 2 are, Br − ( a q ) + AgNO 3 ( a q ) → AgBr ( s ) + NO 3 − ( a q ) 2Br − ( a q ) + Pb ( NO 3 ) 2 ( a q ) → PbBr 2 ( s ) + 2 NO 3 − ( a q ) 2Br − ( a q ) + BaCl 2 ( a q ) → BaBr 2 ( a q ) + 2 Cl − ( a q ) The reaction of Br − ion with the dilute solutions of AgNO 3 , BaCl 2 and Pb ( NO 3 ) 2 results in the formation of two water insoluble compounds AgBr and PbBr 2 and one soluble compound BaBr 2 . Therefore, Br − ion will not form precipitate with all the three dilute solutions. The chemical reaction of NO 3 − ion with the dilute solutions of AgNO 3 , BaCl 2 and Pb ( NO 3 ) 2 are, NO 3 − ( a q ) + AgNO 3 ( a q ) → No reaction NO 3 − ( a q ) + Pb ( NO 3 ) 2 ( a q ) → No reaction NO 3 − ( a q ) + BaCl 2 ( a q ) → Ba ( NO 3 ) 2 ( a q ) + 2 Cl − ( a q ) Nitrate ion ( NO 3 − ) will not show any reaction with AgNO 3 and Pb ( NO 3 ) 2 as both the compounds contains similar anion that is nitrate ion

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Chapter 4, Problem 28E

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To determine: The possible anion between Br−, CO32− and NO3− that forms precipitate with the dilute solutions of AgNO3, BaCl2 and Pb( NO3)2 .

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Chapter 4, Problem 27E

Chapter 4, Problem 29E

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The possible anion between Br − , CO 3 2 − and NO 3 − that forms precipitate with the dilute solutions of AgNO 3 , BaCl 2 and Pb ( NO 3 ) 2 .

To determine: The possible anion between Br−, CO32− and NO3− that forms precipitate with the dilute solutions of AgNO3, BaCl2 and Pb( NO3)2 .

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Chapter 4 Solutions