Divide and show the steps of Problem Example 9.3 in chapter 9 from the textbook into the format of “Given”, “Find” and “Solution” sections.

Answer to Problem 27P
The mass of water stored after 5 minutes in tank (a) is 600 kg and in tank (b) is 300 kg, and the time taken to fill tank (a) and tank (b) of volume
Explanation of Solution
Given:
Volume of each tank
Density of water
Rate at which fluid enters tank is
Find:
The mass of water stored after 5 minutes in each tanks and also find the time taken to fill the tanks of volume
Solution:
Refer figure 1. Water enters the tank (a) at rate of
Formula for the relationship of conservation of mass is,
Consider the expression for rate of accumulation or depletion of fluid in the control volume is,
Substitute equation (2) in equation (1).
In figure 1, there is no disposal of water from the tank through any opening. Therefore, the rate at which the fluid leaves the control volume is zero. Therefore, equation (3) becomes,
As the water is filled inside the control volume at rate of
Formula to determine how much mass each tank can hold is,
Formula to determine the time taken to fill the tank (a) is,
Convert the unit of time taken from seconds to minutes.
Refer to Figure 2. Water enters the tank (b) at rate of
From equation (3),
As the water is filled inside the tank at rate of
Formula to determine the time taken to fill the tank (b) is,
Convert the unit of time taken from seconds to minutes.
Conclusion:
Hence, the mass of water stored after 5 minutes in tank (a) is 600 kg and in tank (b) is 300 kg, and the time taken to fill tank (a) and tank (b) of volume
Want to see more full solutions like this?
Chapter 4 Solutions
EP WEBASSIGN FOR MOAVENI'S ENGINEERING
- For the gravity concrete dam shown in the figure, the following data are available: Unit weight of concrete (7)-2.4 ton/m Neglect Wave pressure, silt pressure, ice force and earth quake force) -0.65, (7)-1 ton/m' Solve on paper and sketch Find factor of safety against sliding and overturning (F.Sa & F.S), If heel and toe stresses (Pain & P) are 57.17ton/m2 and 84.53 ton/m² respectively. Solve in table on paper w.s.l 83m 10m 8m 80marrow_forward1. Find moments of inertia around horizontal and vertical centroid axes for given 6 cross sections. 30cm 4) "T 0cm 1116 5) 20cm 5cm 6)arrow_forward1. Find moments of inertia around horizontal and vertical centroid axes for given 6 cross sections. 1) 30cm 5cm 10cm 20cm 2) 3)arrow_forward
- An anchored sheet-pile bulkhead is shown in the figure below. Let L₁ = 2 m. L₂ =6 m. l₁ = 1 m = 17 kN/m². sat -18.86 kN/m², '=32°, and c=27 kN/m². Use the free earth support method. Anchor Sand = 0 Water table L Sand Ysat c' = 0 Clay = 0 1. Determine the theoretical depth of embedment, D. (Enter your answer to three significant figures.) D= m 2. Calculate the anchor force per unit length of the sheet-pile wall. (Enter your answer to three significant figures.) F= kN/marrow_forwardCalculate the dry mass of activated sludge (✗a) produced in wastewater treatment system where the flow rate is 7,500 m³/day, the BOD concentration in the primary effluent (i.e., the BOD concentration in the wastewater going to the aeration basin) is 75 mg/L, the soluble BOD concentration in the liquid effluent of the secondary clarifier is 10 mg/L, and the system is operating with an SRT of 3 days. Assume true yield is 0.5 g VSS per g BOD and the decay rate (i.e., bч or kd) is equal to 0.1 days 1. Assume the system does not achieve nitrification and that the mass of cell debris, nonbiodegradable VSS, and influent inert TSS is negigible. Express your answer in kg/day and round to the nearest 0.1.arrow_forwardIn a school, there are three clubs: Drama Club, Music Club, and debating Club. Some students are members of multiple clubs, while others are only members of one club. a. How would you represent this scenario using set notation and Venn Diagram?arrow_forward
- Determine the required volume of a completely mixed activated sludge aeration tank for a conventional activated sludge system treating a design flow rate of 34,560 m³/d, where the effluent standards are 30.0 mg/L for BOD5 and 30.0 mg/L for total suspended solids (TSS). Assume that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the BOD5 concentration leaving the primary clarifier is 128 mg/L that the MLVSS concentration (Xa) is 2,500 mg/L. Assume the following values for the growth constants: • K = 100 mg/L BOD5 • μm = 2.5 d−1 • kd = 0.050 d 1 Y = 0.50 mg VSS/mg BOD5 removed Express your answer in m³ and round to the nearest integer.arrow_forwardDetermine the daily volume of methane and total gas produced in an anaerobic digester if the biosolids flow rate is 200 m³/d and the COD concentration going into the reactor is 5,000 g/m³. Assume yield is 0.05 g VSS/g COD, that there is 90% COD removal, and that methane is 50% of the total gas volume. Assume that actual gas production at the operating temperature is 0.4 L of CH4 per g of COD. Express your answer in m³/d and round to the nearest integer.arrow_forwardConsidering the following stoichiometry shown below, calculate the theoretical true yield of bacteria that use the organic molecule butyrate (C4 H7O2¯) as their source of energy. Express your answer with the units of grams of C5 H7O2 N per gram of O2 and round to the nearest 0.01. Stoichiometric relationship for the microbial oxidation of butyrate with O₂ as terminal electron acceptor 2C4H;O, +502+NHẠ* → C5 H7O2 N + 5H2O+ HCO3 + CO2 Stoichiometric relationship for the complete oxidation of butyrate C4H7O2 +502 + H+ →4CO2+4H₂Oarrow_forward
- Refer to the figure below. Given: L₁ = 4m, L2 = 8 m, l₁ = l2 = 2 m, y = 16 kN/m³, Ysat = 18.5 kN/m³, and ' = 26°. Use the charts presented below the answer fields. Sand c' = 0 Anchor L₁ Water table Sand Ysat c' 0 $' Sand c' = 0 1. Determine the theoretical depth of penetration. (Enter your answer to two significant figures.) D= m 2. Determine the anchor force per unit length. (Enter your answer to two significant figures.) F= kN/m 3. Determine the maximum moment in the sheet pile. (Enter your answer to two significant figures.) CDL₁ Mmax = 0.5 kN-m/m 0.4- -24= &' 26° 0.3 -28° 30° 32° 0.2 34° 36° 38° 0.1 0.0 0.1 0.2 0.3 0.4 0.5 1.18 1.16 1.14 1.12 1.10 1.08 1.06 1.04 4₁/(L₁+ L₂2) L₁ 4₁+12 0.3 0.2 = 0.4arrow_forwardFor the gravity concrete dam shown in the figure, the following data are available: - Unit weight of concrete (Yeone) = 2.4 ton/m³ - Horizontal earth quake coefficient (Kh) = 0.1 Neglect( Wave pressure, silt pressure, ice force) H=0.65, (Ywater) -1 ton/m³ Find :- a- heel and toe stresses (Pain & Pmas) b- factor of safety against sliding and overturning (F.S. & F.Sover). Solve in table on paper W 8m 6m 8m 94m 0.9arrow_forwardA market segment consists of 500 individuals. A Logit mode choice model (with logit parameter equal to 1) has been estimated for this market resulting in the following utility function: U = ẞm 0.40C 0.037 where C is out-of-pocket cost in $ and T is travel time in min. Values of ẞm are: Bus: 0.00; Rail: 0.50; Car: 1.50. For a particular origin-destination pair, the cost of a car trip is $2 and the duration 8 minutes, a rail trip is $1.50 and takes 12 minutes, while a bus takes 20 minutes and costs $1.25. a. Predict the number of trips for each mode. b. Which one of the following policies would lead to the largest increase in bus passengers? Why? (i) An increase in the price of gas that increases the cost of a car trip to $3, while all other parameters remain constant. (ii) Introducing an express service that decreases the travel time of the rail to 10 min, while all other parameters remain constant. (iii) Decrease the cost of the bus to $1, while all other parameters remain constant.arrow_forward
- Engineering Fundamentals: An Introduction to Engi...Civil EngineeringISBN:9781305084766Author:Saeed MoaveniPublisher:Cengage LearningResidential Construction Academy: House Wiring (M...Civil EngineeringISBN:9781285852225Author:Gregory W FletcherPublisher:Cengage Learning

