Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN: 9781305084766
Author: Saeed Moaveni
Publisher: Cengage Learning
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Chapter 4, Problem 25P
To determine

Divide the example problem 8.3 in chapter 8 using the 4.2 section described in textbook into the format “Given” ,“Find” , and  “Solution”.

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Answer to Problem 25P

The example problem 8.3 in chapter 8 is divided using the 4.2 section described in textbook into the format “Given” ,“Find” , and  “Solution”, and the total distance travelled by the car is 50347.2m and the average speed of the car over its entire distance is 99.2kmh.

Explanation of Solution

Given:

Car accelerates at speed of 100kmh in 15 seconds from rest,

The car moves with constant speed of 100kmh for about 30 minutes,and

The car decelerates to a full stop in 10 seconds.

Find:

Find the total distance travelled by the car and also find its average speed over this distance.

Solution:

The car speed is linearly increased from zero to 100kmh for the first 15 seconds.

Therefore, the average speed of the car is 50kmh for this period.

Formula to determine the distance travelled during this period (t1) is,

d1=(time)(averagespeed)=(15s)(50kmh)(1h3600s)(1000m1km)      [1h=3600s,and1km=1000m]=208.3m

For the next 30 minutes (1800 s), the car travels with a constant speed of 100kmh.

Formula to determine the distance travelled during this period (t2) is,

d2=(time)(averagespeed)=(1800s)(100kmh)(1h3600s)(1000m1km)      [1h=3600s,and1km=1000m]=50000m

For the last 10 sec, the car decelerates at a constant speed of 100kmh to zero and attains a full stop of the car.

Therefore, the average speed of the car during the last 10 sec is also 50kmh for this period

Formula to determine the distance travelled during this period (t3) is,

d3=(time)(averagespeed)=(10s)(50kmh)(1h3600s)(1000m1km)      [1h=3600s,and1km=1000m]=138.9m

Formula to determine the total distance covered by the car is,

d=d1+d2+d3=208.3m+50000m+138.9m=50347.2m

Convert the unit of total distance from m to km

d=50347.2m=50.3472×103m=50.3472km

Formula to determine the average speed of the car for the entire duration of the travel is,

Vaverage=distancetravelledtime=50347.2m1825s=27.58ms

Convert the unit of average speed from ms to kmh.

Vaverage=(27.58ms)(3600s1h)(1km1000m)[1h=3600s,and1km=1000m]=99.2kmh

Conclusion:

Hence, the example problem 8.3 in chapter 8 is divided using the 4.2 section described in textbook into the format “Given” ,“Find” , and  “Solution”,

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