
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119227946
Author: Willard
Publisher: VST
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Question
Chapter 4, Problem 24AE
(a)
Interpretation Introduction
Interpretation:
The specific heat of the metal has to be given.
Concept introduction:
The specific heat is the amount of heat energy needed to raise the temperature of
(b)
Interpretation Introduction
Interpretation:
The possible metal iron or lead has to be given.
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For Raman spectroscopy/imaging, which statement is not true regarding its disadvantages?
a) Limited spatial resolution.
b) Short integration time.
c) A one-dimensional technique.
d) Weak signal, only 1 in 108 incident photons is Raman scattered.
e) Fluorescence interference.
Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40.
a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L)
b) Calculate the molar absorptivity, a, of the 1645 cm-1 band
c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I).
d) Calculate x for the 1645 cm-1 band
I need help with the follloaing
Chapter 4 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 4.1 - Prob. 4.1PCh. 4.2 - Prob. 4.2PCh. 4.5 - Prob. 4.3PCh. 4.5 - Prob. 4.4PCh. 4.5 - Prob. 4.5PCh. 4 - Prob. 1RQCh. 4 - Prob. 2RQCh. 4 - Prob. 3RQCh. 4 - Prob. 4RQCh. 4 - Prob. 5RQ
Ch. 4 - Prob. 6RQCh. 4 - Prob. 7RQCh. 4 - Prob. 8RQCh. 4 - Prob. 9RQCh. 4 - Prob. 10RQCh. 4 - Prob. 11RQCh. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - Prob. 1PECh. 4 - Prob. 2PECh. 4 - Prob. 3PECh. 4 - Prob. 4PECh. 4 - Prob. 5PECh. 4 - Prob. 6PECh. 4 - Prob. 7PECh. 4 - Prob. 8PECh. 4 - Prob. 9PECh. 4 - Prob. 10PECh. 4 - Prob. 11PECh. 4 - Prob. 12PECh. 4 - Prob. 13PECh. 4 - Prob. 14PECh. 4 - Prob. 15PECh. 4 - Prob. 16PECh. 4 - Prob. 17PECh. 4 - Prob. 18PECh. 4 - Prob. 19PECh. 4 - Prob. 20PECh. 4 - Prob. 21PECh. 4 - Prob. 22PECh. 4 - Prob. 23AECh. 4 - Prob. 24AECh. 4 - Prob. 25AECh. 4 - Prob. 26AECh. 4 - Prob. 27AECh. 4 - Prob. 28AECh. 4 - Prob. 29AECh. 4 - Prob. 30AECh. 4 - Prob. 31AECh. 4 - Prob. 32AECh. 4 - Prob. 33AECh. 4 - Prob. 34AECh. 4 - Prob. 35AECh. 4 - Prob. 36AECh. 4 - Prob. 37AECh. 4 - Prob. 38AECh. 4 - Prob. 39AECh. 4 - Prob. 44CECh. 4 - Prob. 45CECh. 4 - Prob. 46CE
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- For a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forwardI need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forward
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- Can you help me understand the CBC method on metal bridging by looking at this problem?arrow_forwardA partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forward
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