EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 4, Problem 21E
Interpretation Introduction

(a)

Interpretation:

The number of neutrons in an atom of hydrogen-1 is to be predicted.

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 21E

The number of neutrons in atom of hydrogen-1 is 0.

Explanation of Solution

The mass number of hydrogen-1 is 1 and atomic number is also 1.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=11=0

Thus, the number of neutrons in atom of hydrogen-1 is 0.

Conclusion

The number of neutrons in an atom of hydrogen-1 is 0.

Interpretation Introduction

(b)

Interpretation:

The number of neutrons in an atom of carbon-13 is to be predicted.

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 21E

The number of neutrons in an atom of carbon-13 is 7.

Explanation of Solution

The mass number of carbon-13 is 13 and atomic number is 6.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=136=7

Thus, the number of neutrons in atom of carbon-13 is 7.

Conclusion

The number of neutrons in an atom of carbon-13 is 7.

Interpretation Introduction

(c)

Interpretation:

The number of neutrons in an atom of cobalt-59 is to be predicted.

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 21E

The number of neutrons in an atom of cobalt-59 is 32.

Explanation of Solution

The mass number of cobalt-59 is 59 and atomic number is 27.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=5927=32

Thus, the number of neutrons in atom of cobalt-59 is 32.

Conclusion

The number of neutrons in an atom of cobalt-59 is 32.

Interpretation Introduction

(d)

Interpretation:

The number of neutrons in an atom of iodine-127 is to be predicted.

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 21E

The number of neutrons in an atom of iodine-127 is 74.

Explanation of Solution

The mass number of iodine-127 is 127 and atomic number is 53.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=12753=74

Thus, the number of neutrons in an atom of iodine-127 is 74.

Conclusion

The number of neutrons in an atom of iodine-127 is 74.

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Chapter 4 Solutions

EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM

Ch. 4 - Prob. 11CECh. 4 - Prob. 12CECh. 4 - Prob. 1KTCh. 4 - Prob. 2KTCh. 4 - Prob. 3KTCh. 4 - Prob. 4KTCh. 4 - Prob. 5KTCh. 4 - Prob. 6KTCh. 4 - Prob. 7KTCh. 4 - Prob. 8KTCh. 4 - Prob. 9KTCh. 4 - Prob. 10KTCh. 4 - Prob. 11KTCh. 4 - Prob. 12KTCh. 4 - Prob. 13KTCh. 4 - Prob. 14KTCh. 4 - Prob. 15KTCh. 4 - Prob. 16KTCh. 4 - Prob. 17KTCh. 4 - Prob. 18KTCh. 4 - Prob. 19KTCh. 4 - Prob. 20KTCh. 4 - Prob. 21KTCh. 4 - Prob. 22KTCh. 4 - Prob. 23KTCh. 4 - Prob. 24KTCh. 4 - Prob. 25KTCh. 4 - Prob. 1ECh. 4 - Prob. 2ECh. 4 - Prob. 3ECh. 4 - Prob. 4ECh. 4 - Prob. 5ECh. 4 - Prob. 6ECh. 4 - Prob. 7ECh. 4 - Prob. 8ECh. 4 - Prob. 9ECh. 4 - Prob. 10ECh. 4 - Prob. 11ECh. 4 - Prob. 12ECh. 4 - Prob. 13ECh. 4 - Prob. 14ECh. 4 - Prob. 15ECh. 4 - Prob. 16ECh. 4 - Prob. 17ECh. 4 - Prob. 18ECh. 4 - Prob. 19ECh. 4 - Prob. 20ECh. 4 - Prob. 21ECh. 4 - Prob. 22ECh. 4 - Prob. 23ECh. 4 - Prob. 24ECh. 4 - Prob. 25ECh. 4 - Prob. 26ECh. 4 - Prob. 27ECh. 4 - Prob. 28ECh. 4 - Prob. 29ECh. 4 - Prob. 30ECh. 4 - Prob. 31ECh. 4 - Prob. 32ECh. 4 - Prob. 33ECh. 4 - Prob. 34ECh. 4 - Prob. 35ECh. 4 - Prob. 36ECh. 4 - Prob. 37ECh. 4 - Prob. 38ECh. 4 - Prob. 39ECh. 4 - Prob. 40ECh. 4 - Prob. 41ECh. 4 - Prob. 42ECh. 4 - Prob. 43ECh. 4 - Prob. 44ECh. 4 - Prob. 45ECh. 4 - Prob. 46ECh. 4 - Prob. 47ECh. 4 - Prob. 48ECh. 4 - Prob. 49ECh. 4 - Prob. 50ECh. 4 - Prob. 51ECh. 4 - Prob. 52ECh. 4 - Prob. 53ECh. 4 - Prob. 54ECh. 4 - Prob. 55ECh. 4 - Prob. 56ECh. 4 - Prob. 57ECh. 4 - Prob. 58ECh. 4 - Prob. 59ECh. 4 - Prob. 60ECh. 4 - Prob. 61ECh. 4 - Prob. 62ECh. 4 - Prob. 63ECh. 4 - Prob. 64ECh. 4 - Prob. 65ECh. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - Prob. 68ECh. 4 - Prob. 69ECh. 4 - Prob. 70ECh. 4 - Prob. 71ECh. 4 - Prob. 72ECh. 4 - Prob. 73ECh. 4 - Prob. 74ECh. 4 - Prob. 75ECh. 4 - Prob. 76ECh. 4 - Prob. 77ECh. 4 - Prob. 78ECh. 4 - Prob. 79ECh. 4 - Prob. 80ECh. 4 - Prob. 81ECh. 4 - Prob. 82ECh. 4 - Prob. 83ECh. 4 - Prob. 84ECh. 4 - Prob. 85ECh. 4 - Prob. 86ECh. 4 - Prob. 87ECh. 4 - Prob. 88ECh. 4 - Prob. 89ECh. 4 - Prob. 90ECh. 4 - Prob. 91ECh. 4 - Prob. 92ECh. 4 - Prob. 93ECh. 4 - Prob. 94ECh. 4 - Prob. 95ECh. 4 - Prob. 96ECh. 4 - Prob. 97ECh. 4 - Prob. 98ECh. 4 - Prob. 1STCh. 4 - Prob. 2STCh. 4 - Prob. 3STCh. 4 - Prob. 4STCh. 4 - Prob. 5STCh. 4 - Prob. 6STCh. 4 - Prob. 7STCh. 4 - Prob. 8STCh. 4 - Prob. 9STCh. 4 - Prob. 10STCh. 4 - Prob. 11STCh. 4 - Prob. 12STCh. 4 - Prob. 13STCh. 4 - Prob. 14STCh. 4 - Prob. 15STCh. 4 - Prob. 16STCh. 4 - Prob. 17STCh. 4 - Prob. 18ST
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