Explanation Given: The system of equations is: x + 2 y + z = 5 3 x − 8 y = 17 2 y + z = − 2 Calculation: Consider the equations: x + 2 y + z = 5 …...…... (1) 3 x − 8 y = 17 …...…... (2) 2 y + z = − 2 …...…... (3) Consider the equation (3), and rearrange z in terms of y , z = − 2 − 2 y …...…... (4) Substitute − 2 − 2 y for z in equation (1), x + 2 y − 2 − 2 y = 5 x − 2 = 5 x = 7 Substitute − 2 − 2 y for z and 7 for x in equation (2), 3 ( 7 ) − 8 y = 17 − 8 y = 17 − 21 y = 4 8 = 1 2 Substitute 1 2 for y and 7 for x in (4), z = − 2 − 2 ( 1 2 ) = − 2 − 1 = − 3 Thus, the solution of the equations is ( 7 , 1 2 , − 3 )

Intermediate Algebra Books a la Carte Edition PLUS MyLab Math (8th Edition)

8th Edition

ISBN: 9780134578507

Author: John Tobey Jr., Jeffrey Slater, Jenny Crawford, Jamie Blair

Publisher: PEARSON

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Chapter 4, Problem 20RP

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To calculate: The solution to the system of equations x+2y+z=5, 3x−8y=17 and 2y+z=−2 by substitution method.

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Chapter 4, Problem 19RP

Chapter 4, Problem 21RP

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Intermediate Algebra Books a la Carte Edition PLUS MyLab Math (8th Edition)

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The solution to the system of equations x + 2 y + z = 5 , 3 x − 8 y = 17 and 2 y + z = − 2 by substitution method.

Solution Summary: The author calculates the system of equations x+2y+z = 5, 3x-8y = 17 and 2y +z=-2 by substitution method.

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To calculate: The solution to the system of equations x+2y+z=5, 3x−8y=17 and 2y+z=−2 by substitution method.

Want to see the full answer?

Chapter 4 Solutions