EBK C++ PROGRAMMING: FROM PROBLEM ANALY
EBK C++ PROGRAMMING: FROM PROBLEM ANALY
8th Edition
ISBN: 9781337514491
Author: Malik
Publisher: CENGAGE LEARNING - CONSIGNMENT
Question
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Chapter 4, Problem 1TF

a)

Program Plan Intro

To prove whether the given statement is true or false.

a)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Explanation:

The flow of control in programming refers to the order or the sequence in which the function calls, instructions and statements are executed by the compiler. There are two types of programming - procedural and object-oriented programming paradigms.

In procedural programming, the flow of control is same as the sequence in which the instructions and statements are written.

But in an object-oriented programming language, the flow of control differs due to function calls.

Conclusion:

Hence, in object-oriented programming paradigm also, the flow of control indicates the order in which statements execute in a program.

b)

Program Plan Intro

To prove that the given statement is true or false.

b)

Expert Solution
Check Mark
Program Description Answer

The given statement is False.

Explanation of Solution

Explanation:

The equality operator in C++ comprises of two equal symbols, that is, ==. The equality operator is used together with if statement in order to verify whether the values of two variables are equal or not.

The single equal symbol, =, is called the assignment operator which is used to assign values to variables.

Conclusion:

Hence, the given statement is False.

c)

Program Plan Intro

To prove that the given statement is true or false.

c)

Expert Solution
Check Mark
Program Description Answer

The given statement is False.

Explanation of Solution

Explanation:

When an if statement is written, the expression is written inside a pair of round brackets that does not ends with a semicolon. Whereas if the semicolon is placed after the expression in the if statement, it will not generate an expected result. Ending an if statement with a semicolon means ending the condition. It will check the condition but will end it in the same line and the logic will not be applied to the further statements.

Conclusion:

Hence, the given statement is False.

(d)

Program Plan Intro

To prove that the given statement is true or false.

(d)

Expert Solution
Check Mark
Program Description Answer

The given statement is False.

Explanation of Solution

Explanation:

An if statement should have a corresponding else or not is decided by the requirements of the program. If the program requires, then every if statement will have a corresponding else statement. Otherwise, if the program does not require, the if statement will not have a corresponding else part.

Whether an if statement will have a corresponding else part or not, is only decided by the program requirements and is not mandatory. A program will execute properly if only an if statement is written.

Conclusion:

Hence, the given statement is False.

(e)

Program Plan Intro

To prove whether the given statement is true or false.

(e)

Expert Solution
Check Mark
Program Description Answer

The given statement is False.

Explanation of Solution

Given statement:

The expression in the if statement:

if(score=30)

grade = ‘A’;

Explanation:

The expression inside the if statement assigns the variable score with a value of 30. The assignment statement is always True. Hence, in all the scenarios, the if statement will always evaluate to True and the grade variable will be assigned value ‘A’.

Conclusion:

Thus, the given statement is True.

(f)

Program Plan Intro

To prove whether the given statement is true or false.

(f)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Given statement:

The expression:

if(ch>=’A’ && ch<=’Z’)

Explanation:

The given if statement contains two conditions that are combined by “&&” operator. That is, when both the conditions are satisfied only then the if statement will evaluate to True.

For input ch<’A’, the first condition is not satisfied hence the if statement evaluates to False.

For input ch>=’Z’, both the conditions are satisfied only and only if ch=’Z’ but not for ch>’Z’.

Thus, for either of the inputs, the if statement evaluates to False.

Conclusion:

Hence, the given statement is True.

g)

Program Plan Intro

To prove whether the given statement is true or false.

g)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Given statement:

The given code is as follows.

cin >> num;
if(num > 5)
  cout << num;
  num=0;
else
  cout << “Num is zero” << endl;

Explanation:

In the given code, the if statement will be executed only when the input is greater than 5, otherwise the else statement will be executed.

The input for the given code is 5. Since the input is not greater than 5, the if statement will not be executed.

Here, for the input of 5, the else statement will be executed, and the output will be “Num is zero”.

Conclusion:

Hence, the given statement is True.

(h)

Program Plan Intro

To prove whether the given statement is true or false.

(h)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Explanation:

The result of a logical expression is either True or False. That is, a logical expression will always give a Boolean result.

A Boolean value can only be assigned to a Boolean variable but not to an int variable.

Conclusion:

Hence, the given statement is True.

(i)

Program Plan Intro

To prove whether the given statement is true or false.

(i)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Explanation:

The given expression is a combination of two statements. The first statement is x>0 which checks if the value of x is greater than 0. The second statement is “!” which inverts the result of the expression, x>0. It means that the “!” operator makes the expression as x<0.

Hence, the expression, x<0, can only be true for negative numbers.

Conclusion:

Thus, the given statement is True.

(j)

Program Plan Intro

To prove whether the given statement is true or false.

(j)

Expert Solution
Check Mark
Program Description Answer

The given statement is False.

Explanation of Solution

Explanation:

In C++, there are three logical operators. They are “&&”or AND operator, “||” or OR operator, and “!” or NOT operator.

The “!” operator is a logical operator.

The “!=” operator is an equality operator since it checks if one value is not equal to another value.

Conclusion:

Hence, the given statement is False.

(k)

Program Plan Intro

To prove whether the given statement is true or false.

(k)

Expert Solution
Check Mark
Program Description Answer

The given statement is True.

Explanation of Solution

Explanation:

In C++, there are four types of simple data types. They are integer, float, string, and boolean.

The expression in the switch statement is usually a variable. A variable can have any one of the simple data types.

In some cases when the switch contains an expression, the result of the expression can only evaluate to a value of the simple data type.

Conclusion:

Hence, the given statement is True.

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Students have asked these similar questions
In C programming language
Direction: Read each sentence/ situation carefully and select the BEST answer among the choices. 1. It is a Boolean expression that tells when the loop will exit. 2. The sequence that makes up the loop body may either be a block of Turbo C statements or a single Turbo C statement. 3. In Turbo C it is a reserved word. 4. Its values determine the number of times the loop iterates. 5. It is the second type of open-ended loop. Condition For Loop Statement For Do while Loop
All of the following are examples of nesting control structure EXCEPT: OHaving a loop inside an if statement body. OHaving a function call inside the body a loop OHaving one loop structure inside another loop structure Having an if-elif statement inside a loop body
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