Chapter 4, Problem 1RQ

Find 210 div 17 and 210 mod 17.

To determine

Find $210\text{}\text{div 17}$ and $\text{210}\text{mod}17$.

Answer to Problem 1RQ

$\begin{array}{l}210\text{ div}\text{17}=12\text{and }\\ \text{210 mod 17}=6\end{array}$

Explanation of Solution

Given information:

$210\text{}\text{div 17}$ And $\text{210}\text{mod}17$.

Concept used:

Div. and mod are operator for division algorithm.

The division algorithm states that if $a$ is divided by $b$, then unique integer quotient $q$ and remainder $r$ is obtained.

$a=bq+r$

Here,

  $\begin{array}{l}q=a\text{div}b\\ r=a\mathrm{mod}b\end{array}$

Calculation:

$210$ Can be expressed as

  $210=17.12+6$

So,

  $\begin{array}{l}210\text{div 17}=12\text{and }\\ \text{210}\mathrm{mod}17=6\end{array}$

Conclusion:

$\begin{array}{l}210\text{div 17}=12\text{and }\\ \text{210}\mathrm{mod}17=6\end{array}$