DELMAR'S STANDARD TEXT OF ELECTRICITY
6th Edition
ISBN: 9780357323380
Author: Herman
Publisher: CENGAGE C
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Chapter 4, Problem 1RQ
To determine
Whether the north magnetic pole of the earth is a north polarity or a south polarity?
Expert Solution & Answer
Answer to Problem 1RQ
The north magnetic pole of the earth is a south polarity.
Explanation of Solution
Description:
The earth itself contains magnetic poles. As unlike poles attract each other, the north magnetic pole of a compass needle is attracted to the south magnetic pole of the earth and vice versa.
Hence the north magnetic pole is a geographic south pole.
Conclusion:
The north magnetic pole is a geographic south pole.
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Students have asked these similar questions
Create the PLC ladder logic diagram
for the logic gate circuit displayed in
Figure 7-35. The pilot light red (PLTR)
output section has three inputs: PBR,
PBG, and SW. Pushbutton red (PBR)
and pushbutton green (PBG) are inputs
to an XOR logic gate. The output of the
XOR logic gate and the inverted switch
SW) are inputs to a two-input AND
logic gate. These inputs generate the
pilot light red (PLTR) output.
The two-input AND logic gate output
is also fed into a two-input NAND logic
PBR
PBG
SW
TSW
PLTR
Figure 7-35. Logic gate circuit for Example 7-3.
PLTW
Goodheart-Willcox Publisher
gate. The temperature switch (TSW) is the other input to the NAND logic gate. The output generated from
the NAND logic gate is labeled pilot light white (PLTW).
Imaginary Axis (seconds)
1
6. Root locus for a closed-loop system with L(s) =
is shown below.
s(s+4)(s+6)
15
10-
0.89
0.95
0.988
0.988
-10
0.95
-15
-25
0.89
20
Root Locus
0.81
0.7
0.56
0.38
0.2
5
10
15
System: sys
Gain: 239
Pole: -0.00417 +4.89
Damping: 0.000854
Overshoot (%): 99.7
Frequency (rad/s): 4.89
System: sys
Gain: 16.9
Pole: -1.57
Damping: 1
Overshoot (%): 0
Frequency (rad/s): 1.57
0.81
0.7
0.56
0.38
0.2
-20
-15
-10
-5
5
10
Real Axis (seconds)
From the values shown in the figure, compute the following.
a) Range of K for which the closed-loop system is stable.
b) Range of K for which the closed-loop step response will not have any overshoot.
Note that when all poles are real, the step response has no overshoot.
c) Smallest possible peak time of the system. Note that peak time is the smallest
when wa is the largest for the dominant pole.
d) Smallest possible settling time of the system. Note that peak time is the smallest
when σ is the largest for the dominant pole.
For a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these
frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as
f=fHfL, as illustrated in Figure 7.
0dB
Af
-3 dB
Figure 7. Band reject filter response diagram
Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy:
(a) Upper-3db Frequency (fH) =
Hz
(b) Lower-3db Frequency (fL) =
Hz
(c) Bandwidth (Aƒ) =
Hz
(d) Quality Factor (Q) =
Chapter 4 Solutions
DELMAR'S STANDARD TEXT OF ELECTRICITY
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