The point of intersection by graphing the lines.

Question

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Answer 1

Question

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

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Students have asked these similar questions

1) Express these large and small numbers from the Read and Study section in scientific notation: (a) 239,000 miles (b) 3,800,000,000,000 sheets of paper (c) 0.0000000000000000000000167 grams 2) Find all values for the variable x that make these equations true. (a) 5x = 1 (b) 3x = 1/1 9 (c) 4* = 11/ 4 (e) 4* = 64 (g) 10x = 1,000,000 (d) 3x=-3 (f) 2x = = 8 (h) 10x = 0.001

(b) 4) Find an equation to fit each of the following graphs: (a) 20 20 18 16 14 12 10 8 6 4 2 24 22 20 18 16 14 12 10 8 16 A 2 -3 -2 -1-0 2 3 4. -1 0 1 2 3. -2 -2

3) Which of the following are equivalent to 3? (There may be more than one that is equivalent!) -1 (a) (9)¯¹ 3. (b) (-3)-1 (c) (-3) -1 (d) -(¯3) (e) 11 3-1 (f) 3-4

Answer 2

Question

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

Answer 6

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .

Answer 7

Chapter 4, Problem 1RP

To determine

The point of intersection by graphing the lines.

Answer 8

Expert Solution & Answer

Answer to Problem 1RP

Solution: The point of intersection for equations is $(- 3, 2)$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given: The equations are,

$2 x + 3 y = 0$

$- x + 3 y = 9$

Calculation: The equations are,

$2 x + 3 y = 0$ …… (1).

$- x + 3 y = 9$ …… (2).

Draw the graph for both equations. by finding $x$ intercept and $y$ intercept for equation (1) and equation (2).

Calculate the values for $x$ and $y$ from equation (1).

Substitute $0$ for $x$ in equation (1) to get y intercept.

$\begin{matrix} 2 (0) + 3 y = 0 \\ 0 + 3 y = 0 \\ y = 0 \end{matrix}$

The value obtained for $y = 0$ .

Substitute $- 2$ for $y$ in equation (1).

$\begin{matrix} 2 x + 3 (- 2) = 0 \\ 2 x - 6 = 0 \\ 2 x = 6 \\ x = 3 \end{matrix}$

The value obtained for $x$ is 3.

Draw a line passing through the point $(0, 0)$ and $(3, - 2)$ .

Calculate the values for $x$ and $y$ from equation (1)

Substitute $0$ for $x$ in equation (2) to get y intercept.

$\begin{matrix} - 0 + 3 y = 9 \\ 3 y = 9 \\ y = 3 \end{matrix}$

The value obtained for $y$ is $3$

Substitute 0 for $y$ in equation (2) to get $x$ intercept.

$\begin{matrix} - x + 3 (0) = 9 \\ x = - 9 \end{matrix}$

The value obtained for $x$ is $- 9$

Draw a line passing through the point $(0, 3)$ and $(- 9, 0)$ .

Beginning Algebra: Early Graphing; MathXL -- Valuepack Access Card (12-month access); Worksheets with the Math Coach for Beginning Algebra: Early Graphing (4th Edition), Chapter 4, Problem 1RP

Figure (1)

Figure (1) shows the graph for both equations in which a point $(- 3, 2)$ is the point of intersection.

Conclusion:

Therefore, the intersection point of given equations is $(- 3, 2)$ .