In Problems 1 − 4 , determine whether the function is a polynomial function, a rational function, or neither. For those that are polynomial functions, state the degree. For those that are not polynomial functions, tell why not. f ( x ) = 4 x 5 − 3 x 2 + 5 x − 2
In Problems 1 − 4 , determine whether the function is a polynomial function, a rational function, or neither. For those that are polynomial functions, state the degree. For those that are not polynomial functions, tell why not. f ( x ) = 4 x 5 − 3 x 2 + 5 x − 2
In Problems
1
−
4
, determine whether the function is a polynomial function, a rational function, or neither. For those that are polynomial functions, state the degree. For those that are not polynomial functions, tell why not.
f
(
x
)
=
4
x
5
−
3
x
2
+
5
x
−
2
Expert Solution & Answer
To determine
Whether the function f(x)=4x5−3x2+5x−2 is a polynomial function, a rational function, or neither. If polynomial, state degree, otherwise tell why not.
Answer to Problem 1RE
Solution:
Function f(x)=4x5−3x2+5x−2 is a polynomial function of degree 5
Explanation of Solution
Given Information:
The function, f(x)=4x5−3x2+5x−2
The polynomial function is in standard form of f(x)=anxn+an−1xn−1+....+a1x+a0.
Hence, f(x)=4x5−3x2+5x−2 is a polynomial function.
It has leading term 4x5.
Hence, function f(x)=4x5−3x2+5x−2 is a polynomial function of degree 5.
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A factorization A = PDP 1 is not unique. For A=
7 2
-4 1
1
1
5 0
2
1
one factorization is P =
D=
and P-1
30
=
Use this information with D₁
=
to find a matrix P₁ such that
-
-1 -2
0 3
1
-
- 1
05
A-P,D,P
P1
(Type an integer or simplified fraction for each matrix element.)
Matrix A is factored in the form PDP 1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace.
30 -1
-
1 0 -1
400
0
0 1
A=
3 4 3
0 1 3
040
3 1 3
0 0
4
1
0
0
003
-1 0 -1
Select the correct choice below and fill in the answer boxes to complete your choice.
(Use a comma to separate vectors as needed.)
A basis for the corresponding eigenspace is {
A. There is one distinct eigenvalue, λ =
B. In ascending order, the two distinct eigenvalues are λ₁
...
=
and 2
=
Bases for the corresponding eigenspaces are {
and ( ), respectively.
C. In ascending order, the three distinct eigenvalues are λ₁ =
=
12/2
=
and 3 = Bases for the corresponding eigenspaces are
{}, }, and {
respectively.
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