The Analysis of Biological Data
The Analysis of Biological Data
2nd Edition
ISBN: 9781936221486
Author: Michael C. Whitlock, Dolph Schluter
Publisher: W. H. Freeman
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Chapter 4, Problem 1PP

a)

To determine

To find standard deviation of given data.

a)

Expert Solution
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Answer to Problem 1PP

The standard deviation is 15.95

Explanation of Solution

Given:

Data is,

112, 128, 108, 129, 125, 153, 155, 132, 137

Mean = 131.0 mm Hg and the variance = 254.5

Formula:

  Standard deviation=variance

Calculation:

Using formula,

  Standard deviation=254.5=15.95

b)

To determine

To find sample size of given data

b)

Expert Solution
Check Mark

Answer to Problem 1PP

The sample size is 9.

Explanation of Solution

Given:

Data is,

112, 128, 108, 129, 125, 153, 155, 132, 137

Mean = 131.0 mm Hg and the variance = 254.5

Calculation:

The sample size is a count of selected sample data values.

Therefore, here count is 9 hence sample size is n = 9.

c)

To determine

To find the standard error of the mean

c)

Expert Solution
Check Mark

Answer to Problem 1PP

The standard error of the mean = 5.32

Explanation of Solution

Given:

Data is,

112, 128, 108, 129, 125, 153, 155, 132, 137

Mean = 131.0 mm Hg and the variance = 254.5

Standard deviation s = 15.95 and Sample size = n = 9

Formula:

  Standard error=sn

Calculation:

Using formula,

  Standard error=15.959=5.32

d)

To determine

To find the approximate 95% confidence interval for mean

d)

Expert Solution
Check Mark

Answer to Problem 1PP

Lower limit = 120.4 mm Hg and upper limit = 141.6 mm Hg

Explanation of Solution

Given:

Data is,

112, 128, 108, 129, 125, 153, 155, 132, 137

Mean = 131.0 mm Hg and the variance = 254.5

Standard deviation s = 15.95 and Sample size = n = 9

Standard error = SE = 5.32

Formula:

  Lower limit = Mean  2×SEUpper limit = Mean + 2×SE

Calculation:

2 SE rule of thumb for approximate 95% confidence interval for mean is,

Population mean will be within Mean  2×SEand Mean + 2×SE

Therefore,

  Lower limit = 131  2×5.32=120.4mmHgUpper limit =131 + 2×5.32=141.6mmHg

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