Concept explainers
a)
To find standard deviation of given data.
a)
Answer to Problem 1PP
The standard deviation is 15.95
Explanation of Solution
Given:
Data is,
112, 128, 108, 129, 125, 153, 155, 132, 137
Mean = 131.0 mm Hg and the variance = 254.5
Formula:
Calculation:
Using formula,
b)
To find
b)
Answer to Problem 1PP
The sample size is 9.
Explanation of Solution
Given:
Data is,
112, 128, 108, 129, 125, 153, 155, 132, 137
Mean = 131.0 mm Hg and the variance = 254.5
Calculation:
The sample size is a count of selected sample data values.
Therefore, here count is 9 hence sample size is n = 9.
c)
To find the standard error of the mean
c)
Answer to Problem 1PP
The standard error of the mean = 5.32
Explanation of Solution
Given:
Data is,
112, 128, 108, 129, 125, 153, 155, 132, 137
Mean = 131.0 mm Hg and the variance = 254.5
Standard deviation s = 15.95 and Sample size = n = 9
Formula:
Calculation:
Using formula,
d)
To find the approximate 95% confidence interval for mean
d)
Answer to Problem 1PP
Lower limit = 120.4 mm Hg and upper limit = 141.6 mm Hg
Explanation of Solution
Given:
Data is,
112, 128, 108, 129, 125, 153, 155, 132, 137
Mean = 131.0 mm Hg and the variance = 254.5
Standard deviation s = 15.95 and Sample size = n = 9
Standard error = SE = 5.32
Formula:
Calculation:
2 SE rule of thumb for approximate 95% confidence interval for mean is,
Population mean will be within
Therefore,
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Chapter 4 Solutions
The Analysis of Biological Data
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt