Equations that show the dissociation of CaI 2 and potassium phosphate in water are to be written. Concept Introduction: An ionic compound completely dissociates in water to form ions. Polyatomic ions do not dissociate into individual atoms. While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges. The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol ( aq ) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution). Criteria for balanced ionic and net ionic equations: Material balance: There must be the same number of atoms of each kind on both sides of the arrow. Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Equations that show the dissociation of CaI 2 and potassium phosphate in water are to be written. Concept Introduction: An ionic compound completely dissociates in water to form ions. Polyatomic ions do not dissociate into individual atoms. While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges. The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol ( aq ) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution). Criteria for balanced ionic and net ionic equations: Material balance: There must be the same number of atoms of each kind on both sides of the arrow. Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Equations that show the dissociation of CaI2 and potassium phosphate in water are to be written.
Concept Introduction:
An ionic compound completely dissociates in water to form ions.
Polyatomic ions do not dissociate into individual atoms.
While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges.
The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol (aq) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution).
Criteria for balanced ionic and net ionic equations:
Material balance: There must be the same number of atoms of each kind on both sides of the arrow.
Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Expert Solution & Answer
Answer to Problem 1PE
Solution: The equations are:
a) CaI2(s)→Ca2+(aq)+2I-(aq).
b) K3PO4(s)→3K+(aq)+PO43-(aq).
Explanation of Solution
a) CaI2
CaI2 consists of calcium and iodine atoms. Calcium is in the group 2A and has a charge of 2+ and iodine belongs to the group 7A and has a charge of 1−.
Thus, formula unit of the compound is CaI2 and on dissociation it releases one Ca2+ and two I- ions.
The chemical equation for the dissociation of CaI2 is as follows:
CaI2(s)→Ca2+(aq)+2I-(aq)
CaI2 is a solid, so the symbol (s) is written after it and the ions are in aqueous solution, so the symbol (aq) is written after the ions.
b) Potassium phosphate
The compound potassium phosphate consists of cation K+ and anion PO43−. Thus, according to the charges, the formula of the compound is K3PO4. The equation is expressed by writing the formula of potassium phosphate on the left side and the ions on the right side.
The reaction is as follows:
K3PO4(s)→3K+(aq)+PO43-(aq)
K3PO4 is a solid, so the symbol (s) is written after it and the ions are in an aqueous solution, so the symbol (aq) is written after the ions.
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For a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.
Part V. Label ad match the carbons in compounds Jane and Diane
w/ the corresponding peak no.
in the
Spectra (Note: use the given peak no. To label the carbons, other peak
no are intentionally
omitted)
7 4 2
-0.13
-0.12
-0.11
-0.10
-0.08
8
CI
Jane
1
-0.09
5
210
200
190
180
170
160
150
140
130
120
110
100
-8
90
f1 (ppm)
11
8
172.4
172.0
f1 (ppr
HO
CI
NH
Diane
7
3
11
80
80
-80
-R
70
60
60
2
5
-8
50
40
8.
170
160
150
140
130
120
110
100
90
-0
80
70
20
f1 (ppm)
15
30
-20
20
-60
60
-0.07
-0.06
-0.05
-0.04
-0.03
-0.02
-0.01
-0.00
-0.01
10
-0.17
16
15
56
16
-0.16
-0.15
-0.14
-0.13
-0.12
-0.11
-0.10
-0.09
-0.08
-0.07
-0.06
-0.05
-0.04
17.8 17.6 17.4 17.2 17.0
f1 (ppm)
-0.03
-0.02
550
106
40
30
20
20
-0.01
-0.00
F-0.01
10
0
Consider the reaction of 2-methylpropane with a halogen. With which halogen will the product be almost exclusively 2-halo-2-methylpropane? 1. F2 2. Cl2 3. Br2 4. I2
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell