Equations that show the dissociation of CaI 2 and potassium phosphate in water are to be written. Concept Introduction: An ionic compound completely dissociates in water to form ions. Polyatomic ions do not dissociate into individual atoms. While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges. The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol ( aq ) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution). Criteria for balanced ionic and net ionic equations: Material balance: There must be the same number of atoms of each kind on both sides of the arrow. Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Equations that show the dissociation of CaI 2 and potassium phosphate in water are to be written. Concept Introduction: An ionic compound completely dissociates in water to form ions. Polyatomic ions do not dissociate into individual atoms. While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges. The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol ( aq ) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution). Criteria for balanced ionic and net ionic equations: Material balance: There must be the same number of atoms of each kind on both sides of the arrow. Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Equations that show the dissociation of CaI2 and potassium phosphate in water are to be written.
Concept Introduction:
An ionic compound completely dissociates in water to form ions.
Polyatomic ions do not dissociate into individual atoms.
While writing the chemical equation for dissociation, the formula of the ionic compound and the ions formed from it are written along with their charges.
The number of ions formed by one formula unit of the compound is written in the equation. Usage of the symbol (aq) after a particle means that it is a hydrated ion (surrounded by water molecules in the solution).
Criteria for balanced ionic and net ionic equations:
Material balance: There must be the same number of atoms of each kind on both sides of the arrow.
Electrical balance: The net electrical charge on the left must equal the net electrical charge on the right (the charge does not necessarily have to be zero).
Expert Solution & Answer
Answer to Problem 1PE
Solution: The equations are:
a) CaI2(s)→Ca2+(aq)+2I-(aq).
b) K3PO4(s)→3K+(aq)+PO43-(aq).
Explanation of Solution
a) CaI2
CaI2 consists of calcium and iodine atoms. Calcium is in the group 2A and has a charge of 2+ and iodine belongs to the group 7A and has a charge of 1−.
Thus, formula unit of the compound is CaI2 and on dissociation it releases one Ca2+ and two I- ions.
The chemical equation for the dissociation of CaI2 is as follows:
CaI2(s)→Ca2+(aq)+2I-(aq)
CaI2 is a solid, so the symbol (s) is written after it and the ions are in aqueous solution, so the symbol (aq) is written after the ions.
b) Potassium phosphate
The compound potassium phosphate consists of cation K+ and anion PO43−. Thus, according to the charges, the formula of the compound is K3PO4. The equation is expressed by writing the formula of potassium phosphate on the left side and the ions on the right side.
The reaction is as follows:
K3PO4(s)→3K+(aq)+PO43-(aq)
K3PO4 is a solid, so the symbol (s) is written after it and the ions are in an aqueous solution, so the symbol (aq) is written after the ions.
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For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
81. a. Propose a mechanism for the following reaction:
OH
CH2=CHCHC=N
b. What is the product of the following reaction?
HO
H₂O
N=CCH2CH2CH
OH
HO
CH3CCH=CH2
H₂O
C=N
82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell