PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 4, Problem 19P
To determine
The change in design life of the rigid pavement when the modulus of rupture is changed.
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A 5 tonne wheel load is applied on a pavement and generates a surface deflection of 0.15 mm.
A. If the pavement is 125 mm thick, what is the vertical stress at the top of the subgrade?
B. If the equivalent radius of tyre contact is 100 mm and Poisson’s ratio is 0.3, what is the pavement’s modulus of elasticity
Discuss various tests used for the quality of aggregate used in flexible pavements.
Problem 31: Compute the pavement thickness by expansion pressure method if the expansion
pressure is 0.160 kg/cm? and the average pavement density is 0.0030 kg/cm?.
Chapter 4 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32P
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- An agency uses the following formula to determine pavement condition rating, PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN, where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e−0.0051118 · IRI − 0.0016027 A pavement section has the following distress data. IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI…arrow_forwardQuestion number (26) Highway Engineering civil engineeringarrow_forwardPlease answer part a,barrow_forward
- Comparing Rigid and Flexible Airport Pavement .arrow_forwardPlease explain the questions step by step so I can understand. Please show clear calculations an solutions. Pleaser also explain the concept behind the problemarrow_forward. Say what is the main purpose of the pavement or pavement layers, and then draw the flexible pavement layers respectively.arrow_forward
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