Chapter 4, Problem 19P

The pressure drop ?p in pascals (Pa) for a fluid flowing in a pipe with a sudden increase in diameter is given by:

$\Delta p=\frac{1}{2}{\left[1-{\left(\frac{d}{D}\right)}^2\right]}^2\rho v^2$ where ? is the density of the fluid, v, the velocity of the flow, and d and D are defined in the figure. Write a program in a script file that calculates the press ure drop ?p. When the script file is executed, it requests the user to input the density in kglm³, the velocity in m/s. and values of the nondimensional ratio d/D as a vector. The program displays the inputted values of p and v followed by a (able with the values of d/D in the first column and the corresponding values of ?p in the second column.

Execute the program assuming flow of gasoline (? = 737 kg/m³) at v = 5 m/s and the following ratios of diameters d/D=0.9, 0.8, 0.7, 0.6,

0.5, 0.4, 0.3.