Consider a 7.6-cm-diameter cylindrical lamb meat chunk 1030 kWm3, (p = 1030 Kg/m 3 , c p = 3 .49 kJ/kg .K), k = 0 .456 W/m .K, α = 1 .3 × 10 -7 m 2 /s) . Such a meat chunk intially at 2°C is dropped into boiling water at 95°C with a heat transfer coefficient of 1200 W/m 2 K. The time it takes for the center temperature of the meat chunk to rise to 75°C is (a) 136 min (b) 21.2 min (c) 13.6 min (d) 11.0 min (e) 8.5 min
Consider a 7.6-cm-diameter cylindrical lamb meat chunk 1030 kWm3, (p = 1030 Kg/m 3 , c p = 3 .49 kJ/kg .K), k = 0 .456 W/m .K, α = 1 .3 × 10 -7 m 2 /s) . Such a meat chunk intially at 2°C is dropped into boiling water at 95°C with a heat transfer coefficient of 1200 W/m 2 K. The time it takes for the center temperature of the meat chunk to rise to 75°C is (a) 136 min (b) 21.2 min (c) 13.6 min (d) 11.0 min (e) 8.5 min
Solution Summary: The author explains the time required for the center temperature of the meat chunk to rise to t=71° C and the thermal conductivity of cylindrical lamb.
Consider a 7.6-cm-diameter cylindrical lamb meat chunk 1030 kWm3,
(p = 1030 Kg/m
3
,
c
p
= 3
.49 kJ/kg
.K), k = 0
.456 W/m
.K,
α
= 1
.3
×
10
-7
m
2
/s)
. Such a meat chunk intially at 2°C is dropped into boiling water at 95°C with a heat transfer coefficient of 1200 W/m2 K. The time it takes for the center temperature of the meat chunk to rise to 75°C is
-6-
8 من 8
Mechanical vibration
HW-prob-1
lecture 8 By: Lecturer Mohammed O. attea
The 8-lb body is released from rest a distance xo
to the right of the equilibrium position.
Determine the displacement x as a function of time t,
where t = 0 is the time of release.
c=2.5 lb-sec/ft
wwwww
k-3 lb/in.
8 lb
Prob. -2
Find the value of (c) if the system is critically
damping.
Prob-3
Find Meq and Ceq at point B, Drive eq. of
motion for the system below.
Ш
H
-7~
+
目
T T & T
тт
+
Q For the following plan of building foundation, Determine
immediate settlement at points (A) and (B) knowing that: E,-25MPa,
u=0.3, Depth of foundation (D) =1m, Depth of layer below base level
of foundation (H)=10m.
3m
2m
100kPa
A
2m
150kPa
5m
200kPa
B
W
PE
2
43
R² 80 + 10 + kr³ Ø8=0 +0
R²+J+ kr200
R² + J-) + k r² = 0
kr20
kr20
8+
W₁ =
= 0
R²+1)
R²+J+)
4
lec 8.pdf
Mechanical vibration
lecture 6
By: Lecturer Mohammed C. Attea
HW1 (Energy method)
Find equation of motion and natural frequency for the system shown in fig. by energy
method.
m. Jo
000
HW2// For the system Fig below find
1-F.B.D
2Eq.of motion
8 wn
4-0 (1)
-5-
m
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.