Chapter 4, Problem 170P

d= 3.8m (on the figure of the beam) Determine the equivalent resultant force and determine the equivalent couple moment at point O.

The equivalent resultant force acting on the beam is zero and the resultant couple moment is 7 kN⋅m clockwise. Determine the length b of the triangular load.

Replace the loading acting on the frame by an equivalent resultant force and couple moment acting at point A. 80 lb 60 lb 3 ft 3 ft- 3 ft 3 ft B A 2 ft + 4 ft 75 lb 40 lb

The equivalent resultant force acting on the beam is zero and the resultant couple moment is 7 kN⋅m clockwise. Determine the position a of the triangular load on the beam.

5. Determine the moment about point B for each of the individual three forces acting on the beam, and indicate their directions. F1 = 400 lb F2 = 450 lb %3D B. 0.5 ft 8 ft 7 ft 6 ft 30° F3 = 150 lb

Handle forces F1 and F2 are applied to the electric drill. Replace this force system by an equivalent resultant force and couple moment acting at point O. Express the results in Cartesian vector from. Determine the resultant force and the moment of the resultant forse about the point O. Express your answer in terms of the unit vectors i, j and k.

Determine the resultant moment of forces about the point O? Neglect the beam thickness 10 N NAN

(a) Determine the resultant of the system of parallel forces which act on the folded plate, i.e., replace the three given forces by a resultant force R and moment M about point O. (b) Find the location (i.e., coordinates) where single R will have the same effect as R and M together at O. Solve using the vector approach. B 250 N 300 N 240 mm 120 mm -160 mm 200 mm 200 mm 400 N

The design specifications for the attachment at A for this beam depend on the magnitude and location of the applied loads. Represent the resultant of the three forces and couple by a single force R at A and a couple moment. Take: M 25 kN .m ;a = 30 ; x = 1.6.m 4 kN 2 m -1.5 m- -0.8 m 2 kN 3 kN