Chapter 4, Problem 169P

Problem 6: Replace the given loading system by an equivalent resultant force and specify where the resultant's line of action intersects the member AB measured from A. 1.0 m -2.0 m- 0.5 m 05 m 20 kN 4 kN 10 kN 4.0 m

Reduction of a simple distributed loading

Replace the force system acting on the post by a resultant force, and specify where its lineof action intersects the post AB measured from the mid-point of post AB

Q.1 Replace the force system acting on the frame by an equivalent resultant force and specify where the resultant's line of action intersects member OA, measured from O.F=5 (kN), W=1 (kN). F 3 m Fx= W 2 m 2 m Fy= Fr= Theta= Мо- d=

O 4-154 o Replace the distributed loading with an equivalent resultant force, and specify its location on the beam measured from point A 8 kN/m -4 m-

Replace the force system acting on the frame by an equivalent resultant force, and specify where the resultant's line of action intersects member AB, measured from point A. 40 lb B 2 ft 20 lb 5 ft y A 5 ft X 50 lb 5 4 3 -2 ft

The trapdoor is held in the horizontal plane by two wires. Replace the forces in the wires with an equivalent force R that passes through point A, and determine the y-coordinate of point A.

Replace the distributed loading by an equivalent resultant force and specify its location, measured from point A. 800 N/m A 2 m- -3 m- 200 N/m B

HOME WORK 2.d... Example 2 - Home work Determine the moment produced by force Fabout segment AB of the pipe assembly. Express the result as a Cartesian vector. F= (-201 + 10j + 15k) N 4 m 3 m 4 m Example 3 - Home work