EBK COMPUTER SCIENCE: AN OVERVIEW
12th Edition
ISBN: 8220102744196
Author: BRYLOW
Publisher: PEARSON
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Chapter 4, Problem 16CRP
Program Plan Intro
Hexadecimal notation:
- A bit pattern for hexadecimal notation is “base-16”.
- The hexadecimal system uses 16-digits.
- This notation uses digits “0” to “9” and also characters from “A” to “F”.
| Hex digit | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Decimal value | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Binary value | 0000 | 0001 | 0010 | 0011 | 0100 | 0101 | 0110 | 0111 |
| Hex digit | 8 | 9 | A | B | C | D | E | F |
| Decimal value | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
| Binary value | 1000 | 1001 | 1010 | 1011 | 1100 | 1101 | 1110 | 1111 |
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
Chapter 4 Solutions
EBK COMPUTER SCIENCE: AN OVERVIEW
Ch. 4.1 - What is an open network?Ch. 4.1 - Prob. 2QECh. 4.1 - What is a router?Ch. 4.1 - Prob. 4QECh. 4.1 - Prob. 5QECh. 4.1 - Prob. 6QECh. 4.2 - Prob. 1QECh. 4.2 - Prob. 2QECh. 4.2 - Prob. 3QECh. 4.2 - Prob. 4QE
Ch. 4.2 - Prob. 5QECh. 4.2 - Prob. 6QECh. 4.2 - Prob. 7QECh. 4.2 - Prob. 8QECh. 4.3 - Prob. 1QECh. 4.3 - Prob. 2QECh. 4.3 - Prob. 3QECh. 4.3 - Prob. 4QECh. 4.3 - Prob. 5QECh. 4.4 - Prob. 1QECh. 4.4 - Prob. 2QECh. 4.4 - Prob. 3QECh. 4.4 - What keeps a computer on the Internet from...Ch. 4.5 - Prob. 1QECh. 4.5 - Prob. 2QECh. 4.5 - Prob. 3QECh. 4.5 - Prob. 4QECh. 4.5 - Prob. 5QECh. 4 - Prob. 1CRPCh. 4 - Prob. 2CRPCh. 4 - Prob. 3CRPCh. 4 - Prob. 4CRPCh. 4 - Prob. 5CRPCh. 4 - Prob. 6CRPCh. 4 - Prob. 7CRPCh. 4 - Prob. 8CRPCh. 4 - Prob. 9CRPCh. 4 - Prob. 10CRPCh. 4 - Prob. 11CRPCh. 4 - Prob. 12CRPCh. 4 - Prob. 13CRPCh. 4 - Prob. 14CRPCh. 4 - Prob. 15CRPCh. 4 - Prob. 16CRPCh. 4 - Prob. 17CRPCh. 4 - Prob. 18CRPCh. 4 - Prob. 19CRPCh. 4 - Prob. 20CRPCh. 4 - Prob. 21CRPCh. 4 - Prob. 22CRPCh. 4 - Prob. 23CRPCh. 4 - Prob. 24CRPCh. 4 - Prob. 25CRPCh. 4 - Prob. 26CRPCh. 4 - Prob. 27CRPCh. 4 - Prob. 28CRPCh. 4 - Prob. 29CRPCh. 4 - Prob. 30CRPCh. 4 - Prob. 31CRPCh. 4 - Prob. 32CRPCh. 4 - Prob. 33CRPCh. 4 - Prob. 34CRPCh. 4 - Prob. 35CRPCh. 4 - Prob. 36CRPCh. 4 - Prob. 37CRPCh. 4 - Prob. 38CRPCh. 4 - Prob. 39CRPCh. 4 - Prob. 40CRPCh. 4 - Prob. 41CRPCh. 4 - Prob. 42CRPCh. 4 - Prob. 43CRPCh. 4 - Prob. 44CRPCh. 4 - Prob. 45CRPCh. 4 - Prob. 46CRPCh. 4 - Prob. 47CRPCh. 4 - Prob. 48CRPCh. 4 - Prob. 49CRPCh. 4 - Prob. 50CRPCh. 4 - Prob. 1SICh. 4 - Prob. 2SICh. 4 - Prob. 3SICh. 4 - Prob. 4SICh. 4 - Prob. 5SICh. 4 - Prob. 6SICh. 4 - Prob. 7SICh. 4 - Prob. 8SICh. 4 - Prob. 9SICh. 4 - Prob. 10SICh. 4 - Prob. 11SICh. 4 - Prob. 12SI
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