Explanation Given: The given expression is L − 1 { 1 s 2 − 5 } . Formula used: The formula for the inverse Laplace transform is as follows, L − 1 { k s 2 − k 2 } = sinh k t Linearity property of the inverse Laplace transform is as follows, If a and b be any constant and f and g be any function of s then, L − 1 { a f ( s ) + b g ( s ) } = a L − 1 { f ( s ) } + b L − 1 { g ( s ) } Calculation: Use the property above to write the Laplace transform of the given function

6th Edition

ISBN: 9781284105902

Author: Dennis G. Zill

Publisher: Jones & Bartlett Learning

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Chapter 4, Problem 16CR

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To fill: The blank in the statement “L−1{1s2−5}=_______”.

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Chapter 4, Problem 15CR

Chapter 4, Problem 17CR

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Chapter 4 Solutions

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The blank in the statement “ L − 1 { 1 s 2 − 5 } = _ _ _ _ _ _ _ ”.

Solution Summary: The author explains the formula for the inverse Laplace transform: cL-1left1s2-5right

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To fill: The blank in the statement “L−1{1s2−5}=_______”.

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Chapter 4 Solutions