The molarity of H 2 S solution is to be determined. Concept Introduction: The number of moles is calculated from the following expression: n = m M m …… (1) Here, m is the mass of solute, M m is the molar mass of solute, and n is the number of moles of the solute. The molarity of the solution is determined by the following expression: M = n V …… (2) Here, n is the number of moles of solute, V is the volume of the solution in liters, and M is the molarity of the solution.
The molarity of H 2 S solution is to be determined. Concept Introduction: The number of moles is calculated from the following expression: n = m M m …… (1) Here, m is the mass of solute, M m is the molar mass of solute, and n is the number of moles of the solute. The molarity of the solution is determined by the following expression: M = n V …… (2) Here, n is the number of moles of solute, V is the volume of the solution in liters, and M is the molarity of the solution.
Solution Summary: The author explains how the molarity of H_2TextS solution is determined.
5.
Use the MS data to answer the questions on the next page.
14.0
1.4
15.0
8.1
100-
MS-IW-5644
26.0
2.8
27.0
6.7
28.0
1.8
29.0
80
4.4
38.0
1.0
39.0
1.5
41.0
1.2
42.0
11.2
43.0
100.0
44.0
4.3
79.0
1.9
80.0
2.6
Relative Intensity
40
81.0
1.9
82.0
2.5
93.0
8.7
20-
95.0
8.2
121.0
2.0
123.0
2.0
136.0
11.8
0
138.0
11.5
20
40
8.
60
a.
Br
- 0
80
100
120
140
160
180
200
220
m/z
Identify the m/z of the base peak and molecular ion.
2
b.
Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0,
95.0, 136.0, and 138.0 m/z.
C.
Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to
fragment 43.0 m/z. Be sure to include all electrons and formal charges.
6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium
ion (CsH6N) and show your work.
None
Stereochemistry: Three possible answers- diastereomers, enantiomers
OH
CH₂OH
I
-c=0
21108 1101
41745 HOR
CH₂OH
IL
Но
CH₂OH
TIL
a. Compounds I and III have this relationship with each other: enantiomers
b. Compounds II and IV have this relationship with each other:
c. Compounds I and II have this relationship with each other:
d. *Draw one structure that is a stereoisomer of II, but neither a
diastereomer nor an enantiomer. (more than one correct answer)
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