Chapter 4, Problem 156P

The equivalent resultant force acting on the beam is zero and the resultant couple moment is 7 kN⋅m clockwise. Determine the position a of the triangular load on the beam.

Replace the loading acting on the frame by an equivalent resultant force and couple moment acting at point A. 80 lb 60 lb 3 ft 3 ft- 3 ft 3 ft B A 2 ft + 4 ft 75 lb 40 lb

Determine the resultant moment of the three forces in  aboutthe x axis. the y axis. and the z axis.

(a) Determine the resultant of the system of parallel forces which act on the folded plate, i.e., replace the three given forces by a resultant force R and moment M about point O. (b) Find the location (i.e., coordinates) where single R will have the same effect as R and M together at O. Solve using the vector approach. B 250 N 300 N 240 mm 120 mm -160 mm 200 mm 200 mm 400 N

d= 3.8m (on the figure of the beam) Determine the equivalent resultant force and determine the equivalent couple moment at point O.

The design specifications for the attachment at A for this beam depend on the magnitude and location of the applied loads. Represent the resultant of the three forces and couple by a single force R at A and a couple moment. Take: M 25 kN .m ;a = 30 ; x = 1.6.m 4 kN 2 m -1.5 m- -0.8 m 2 kN 3 kN

Q(2) :Determine the magnitude of F so that the resultant couple moment acting on the beam is 1.5 kN.m clockwise. -0.9 m 2 kN 0.3 m B 2 kN

5. Determine the moment about point B for each of the individual three forces acting on the beam, and indicate their directions. F1 = 400 lb F2 = 450 lb %3D B. 0.5 ft 8 ft 7 ft 6 ft 30° F3 = 150 lb

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