EBK ENGINEERING ECONOMY
16th Edition
ISBN: 9780133819014
Author: Koelling
Publisher: YUZU
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Question
Chapter 4, Problem 143FE
To determine
Calculate the annual value.
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Suppose that under the Plan of Repayment one should pay off the debt in a number of equal end-of-month installments (principal and interest). This is the customary way to pay off loans
on automobiles, house mortgages, etc. A friend of yours has financed $15,000 on the purchase of a new automobile, and the annual interest rate is 6% (0.5% per month).
a. Monthly payments over a 36-month loan period will be how much?
b. How much interest and principal will be paid within three month of this loan?
Click the icon to view the interest and annuity table for discrete compounding when i = 0.5% per month.
a. The monthly payment over a 36-month loan period is $ 456.3. (Round to the nearest cent.)
b. Fill in the table below. (Round to the nearest cent.)
Payment Number
1
2
3
Interest Payment
$
$
$
Principal Repayment
$
$
$
Remaining Loan Balance
$
$
$
Suppose that under the Plan of Repayment one should pay off the debt in a number of equal end-of-month installments (principal and interest). This is the customary way to pay off loans
on automobiles, house mortgages, etc. A friend of yours has financed $15,000 on the purchase of a new automobile, and the annual interest rate is 6% (0.5% per month).
a. Monthly payments over a 36-month loan period will be how much?
b. How much interest and principal will be paid within three month of this loan?
Suppose a certain manufacturer deposits $3, 000 at the beginning of each 3 month period for 8 years in an account paying 8% interest compounded quarterly. (Round your answers to the nearest cent.) (a) How much (in $) will be in the account at the end of the 8 year period? $ Incorrect: Your answer is incorrect. (b) What is the total amount (in $) of interest earned in this account? $ Incorrect: Your answer is incorrect
Chapter 4 Solutions
EBK ENGINEERING ECONOMY
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Twelve payments of 10,000 each are to be repaid...Ch. 4 - Prob. 32PCh. 4 - Automobiles of the future will most likely be...Ch. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - A geothermal heat pump can save up to 80% of the...Ch. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Maintenance expenses for a bridge on the Ohio...Ch. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72PCh. 4 - Prob. 73PCh. 4 - Prob. 74PCh. 4 - Prob. 75PCh. 4 - Prob. 76PCh. 4 - Prob. 77PCh. 4 - Prob. 78PCh. 4 - Prob. 79PCh. 4 - Prob. 80PCh. 4 - Prob. 81PCh. 4 - Prob. 82PCh. 4 - Prob. 83PCh. 4 - Prob. 84PCh. 4 - Prob. 85PCh. 4 - Prob. 86PCh. 4 - Prob. 87PCh. 4 - Prob. 88PCh. 4 - Prob. 89PCh. 4 - Prob. 90PCh. 4 - Prob. 91PCh. 4 - Prob. 92PCh. 4 - Prob. 93PCh. 4 - Prob. 94PCh. 4 - Prob. 95PCh. 4 - Prob. 96PCh. 4 - Prob. 97PCh. 4 - Prob. 98PCh. 4 - Prob. 99PCh. 4 - Prob. 100PCh. 4 - A large bank has increased its annual percentage...Ch. 4 - Prob. 102PCh. 4 - Prob. 103PCh. 4 - Prob. 104PCh. 4 - Prob. 105PCh. 4 - Prob. 106PCh. 4 - Prob. 107PCh. 4 - Prob. 108PCh. 4 - Prob. 109PCh. 4 - Prob. 110PCh. 4 - Prob. 111PCh. 4 - Prob. 112PCh. 4 - Prob. 113PCh. 4 - Prob. 114PCh. 4 - Prob. 115PCh. 4 - Prob. 116PCh. 4 - Prob. 117PCh. 4 - Prob. 118PCh. 4 - Prob. 119PCh. 4 - Prob. 120PCh. 4 - Prob. 121PCh. 4 - Prob. 122PCh. 4 - Prob. 123PCh. 4 - Prob. 124PCh. 4 - Prob. 125PCh. 4 - Prob. 126PCh. 4 - Analyze the truth of this statement, assuming you...Ch. 4 - Prob. 128PCh. 4 - Prob. 129SECh. 4 - Prob. 130SECh. 4 - Prob. 131SECh. 4 - Prob. 132SECh. 4 - Prob. 133CSCh. 4 - Prob. 134CSCh. 4 - Prob. 135CSCh. 4 - Prob. 136FECh. 4 - Prob. 137FECh. 4 - Prob. 138FECh. 4 - Prob. 139FECh. 4 - Prob. 140FECh. 4 - Prob. 141FECh. 4 - Prob. 142FECh. 4 - Prob. 143FECh. 4 - Prob. 144FECh. 4 - Prob. 145FECh. 4 - Prob. 146FECh. 4 - Prob. 147FECh. 4 - Prob. 148FECh. 4 - Prob. 149FECh. 4 - Prob. 150FECh. 4 - Prob. 151FE
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- fee cash flow diagramarrow_forward4.39. What is the present worth of the following series of payments? (a) $5,000 at the end of each six-month period for 12 years at 9% compounded semiannually. $7,000 at the end of each quarter for 10 years at 8% compounded quarterly. (b) (c) $3,500 at the end of each month for five years at 6% compounded monthly.arrow_forward7. Sarah borrows some money to buy a new car. The car dealership allows her to defer payments for 12 months, and Sarah makes 60 end of month payments thereafter. If the original loan is $15321 and interest is 0.75% per month, how much will Sarah's monthly payment be? • $697 $627 $349 $279 $418arrow_forward
- QUESTION 1 Muhammad takes out a loan of $ 2,130, at 8% simple interest, for 8 years. How much will he pay back at the end of year 8? QUESTION 2 Calculate the amount of interest on an investment of AED 103,971 at 8% simple interest for 5 years. QUESTION 3 If you deposit today $7,335 in an account for 6 years and at the end accumulate $10,885, how much compound interest rate (rate of return) you earned on this investment ? QUESTION 4 You will deposit 12,025 at 10% simple interest rate for 9 years, and then move the amount you would receive to an investment account at 12 % compound rate for another 3 years. How much money would you have at the end of the entire period ?arrow_forwardThe force of interest at time is 0.05t. 3 payments equal to 1 are made at the end of years 1, 2, and 3. Find the future value at the end of year 4. a) 3.4 b) 3.6 c)3.8 d) 4.0 e) 4.2arrow_forward1. Find the interest paid on a loan of $2000 for 1 year at a simple interest rate of 7% per year. 2. Find the maturity value of a loan of $49,583 after 18 months. The loan carries a simple interest rate of 8.3% per year. 3. Find the exact interest on a loan of $7500 at 13% annually made on July 17 and due November 30. (Table 11-1) 4. Find the ordinary interest on a loan of $850 at 11% annually made on February 10 and due May 31. (Table 11-1)arrow_forward
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