Explanation Given: Mass of petty thief, m 1 = 75 kg Mass which generates maximum tension T in the rope. m 2 = 5 8 kg Formula Used: According to Newton’s second law of motion: ∑ F = m a Where, m is the mass and a is the acceleration. Calculation: Maximum tension in the rope would be equal to the weight it can support i.e. T = m 2 g Weight of thief acts downwards i.e. m 1 g . Free body diagram for the given situation is: Substitute the values and solve for acceleration ( a )

7th Edition

ISBN: 2818440037979

Author: GIANCOLI

Publisher: PEARSON

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Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

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Chapter 4, Problem 13P

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The strategy used by a thief to climb down through a rope which can’t support the mass of the thief.

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Chapter 4, Problem 12P

Chapter 4, Problem 14P

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