PHYSICS
PHYSICS
5th Edition
ISBN: 2818440038631
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 4, Problem 136P

(a)

To determine

Check whether the puck move or not due to 5.0N force in forward direction.

(a)

Expert Solution
Check Mark

Answer to Problem 136P

Puck will not move.

Explanation of Solution

The mass of puck is 2.0kg, coefficient of static friction between the board and puck is 0.35, coefficient of kinetic friction between the board and puck is 0.25, and the applied force is 5.0N.

The puck will move or not depends on whether the applied force is greater than or lesser than that of the frictional force between the puck and the board. The puck will move if the applied force is greater than that of the frictional force.

Write the expression to calculate the frictional force between the puck and the board.

fs,max=μsN

Here, the maximum value of static frictional force between the puck and the board is fs,max, coefficient of static friction between the board and puck is μs, and the normal reaction force on puck is N.

Write the equation for N.

N=mg

Here, the mass of puck is m and the gravitational acceleration of earth is g.

Rewrite the equation for fs,max by substituting the above relation for N.

fs,max=μsmgearth

Conclusion:

Substitute 0.35 for μs, 2.0kg for m, and 9.8m/s2 for g in the above equation to find fs,max.

fs,max=(0.35)(2.0kg)(9.8m/s2)=6.86N

It is found that fs,max is lesser than that of the applied force 5.0N.

Therefore, the puck cannot move with 5.0N force.

(b)

To determine

Check whether the puck move or not due to 7.5N force in forward direction.

(b)

Expert Solution
Check Mark

Answer to Problem 136P

Puck will move.

Explanation of Solution

The mass of puck is 2.0kg, coefficient of static friction between the board and puck is 0.35, coefficient of kinetic friction between the board and puck is 0.25, and the applied force is 5.0N.

The puck will move or not depends on whether the applied force is greater than or lesser than that of the frictional force between the puck and the board. The puck will move if the applied force is greater than that of the frictional force.

Write the condition for the puck to move

Fapplied>fs,max

Here, the applied force is Fapplied.

Conclusion:

Substitute 7.5N for Fapplied and 6.86N for fs,max in the above condition to check whether it is valid or not.

7.5N>6.86N

It is found that Fapplied>fs,max.

Therefore, the puck cannot move with 5.0N force.

(c)

To determine

Check whether the puck move or not due to 7.5N force in forward direction.

(c)

Expert Solution
Check Mark

Answer to Problem 136P

Puck will move.

Explanation of Solution

The mass of puck is 2.0kg, coefficient of static friction between the board and puck is 0.35, coefficient of kinetic friction between the board and puck is 0.25, and the push force is 6.0N.

Write the equation for net force on the puck.

ma=Fpushμkg

Here, the acceleration of puck is a, coefficient of kinetic friction between the board and puck is μk, and the push force is Fpush.

Conclusion:

Substitute 2.0kg for m, 6.0N for Fpush, 0.25 for μk, and 9.8m/s2 for g in the above equation to find a.

(2.0kg)a=6.0N((6.0N)(9.8m/s2))=6.0N58.8N2.0kg=0.6N/m2

Therefore, the puck can move.

(d)

To determine

Whether the acceleration of puck will be same, lesser than, or greater than that of in earth for the same applied force.

(d)

Expert Solution
Check Mark

Answer to Problem 136P

Acceleration of puck will be greater in moon that in earth.

Explanation of Solution

The mass of puck is 2.0kg, coefficient of static friction between the board and puck is 0.35, coefficient of kinetic friction between the board and puck is 0.25, and the applied force is 6.0N.

Write the equation for net force on the puck.

ma=Fpushμkg

Rewrite the above relation in terms of a.

a=Fpushmμkg

From the above equation it can be seen that the acceleration of puck depends on the gravitational acceleration exerted on puck.

Rewrite the above equation for puck in moon.

amoon=Fpushmμkgmoon

Here, the acceleration of puck in moon is amoon and the gravitational acceleration of moon is gmoon.

The value of gmoon is lesser than that of g.This means that Fpushmμkgmoon is greater than that of Fpushmμkg.It means that the fractional force on puck in moon is less than that in earth. Thus, amoon will be greater than that of a.

Conclusion:

Therefore, the acceleration of puck will be greater in moon that in earth.

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Chapter 4 Solutions

PHYSICS

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Pulleys and inclined planes are examples of...Ch. 4 - Prob. 25CQCh. 4 - Prob. 26CQCh. 4 - Prob. 27CQCh. 4 - Prob. 28CQCh. 4 - Prob. 29CQCh. 4 - Prob. 30CQCh. 4 - Prob. 31CQCh. 4 - Prob. 1MCQCh. 4 - Prob. 2MCQCh. 4 - Prob. 3MCQCh. 4 - Prob. 4MCQCh. 4 - Prob. 5MCQCh. 4 - Prob. 6MCQCh. 4 - Prob. 7MCQCh. 4 - Prob. 8MCQCh. 4 - Prob. 9MCQCh. 4 - Prob. 10MCQCh. 4 - Prob. 11MCQCh. 4 - Prob. 12MCQCh. 4 - Prob. 13MCQCh. 4 - Prob. 14MCQCh. 4 - Prob. 15MCQCh. 4 - Prob. 16MCQCh. 4 - Prob. 17MCQCh. 4 - Prob. 18MCQCh. 4 - Prob. 19MCQCh. 4 - Prob. 20MCQCh. 4 - Prob. 21MCQCh. 4 - Prob. 22MCQCh. 4 - Prob. 23MCQCh. 4 - Prob. 24MCQCh. 4 - Prob. 25MCQCh. 4 - Prob. 26MCQCh. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - 16. A truck driving on a level highway is acted on...Ch. 4 - 17. 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