Chapter 4, Problem 133QP

Interpretation Introduction

Interpretation:

The mass of $\text{Ca}{\left({\text{NO}}_3\right)}_2$ required to prepare a solution of $0.742\text{ mol}$ of $\text{Ca}{\left({\text{NO}}_3\right)}_2$ is to be determined.

Concept Introduction:

The calculation of number of moles is expressed as follows:

$n=\frac{m}{M}$

Here, $n$ is the number of moles, $m$ is the given mass, and $M$ is the molar mass.