Chapter 4, Problem 127IAE

Interpretation Introduction

Interpretation:

Amount of iron (III) oxide must be calculated while processing 100 kg of

Iron (II) sulfate heptahydrate.

Concept introduction:

There are one and two iron atoms in one molecule of iron (II) sulfate heptahydrate and iron (III) oxide respectively.

Two moles of iron (II) sulfate heptahydrate will produce one mole of iron (III) oxide.

${\text{2FeSO}}_{\text{4}}\text{(s)}{\text{.7H}}_{\text{2}}\text{O+}\frac{\text{1}}{\text{2}}{\text{O}}_{\text{2}}\to {\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}{\text{(s)+2H}}_{\text{2}}{\text{SO}}_{\text{4}}{\text{+5H}}_{\text{2}}\text{O}$