Concept explainers
(a)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of mixed number
The improper fraction of
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
The greatest common factor of
Divide numerator and denominator of fraction by
The mixed conversion of
The mixed conversion of
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
(b)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of mixed number
The improper fraction of
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
The mixed conversion of
The mixed conversion of
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
(c)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of mixed number
The improper fraction of
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
The mixed conversion of
The mixed conversion of
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
(d)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of mixed number
The improper fraction of
The third is already in improper fraction that is
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
The greatest common factor of
Divide numerator and denominator of fraction by
The mixed conversion of
The mixed conversion of
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
(e)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of mixed number
The second number is
The third is already in improper fraction that is
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
(f)
Multiply the mixed fractions and reduce to lowest term.

Answer to Problem 11A
The multiplication of fractions is
Explanation of Solution
Given:
The number is
Concept used:
Convert mixed fraction into improper fractions. Multiply all the numerators and denominators of all fractions with each other to get the product and reduce it to lowest form by greatest common factor.
Calculation:
The improper fraction of first mixed number
The improper fraction of second mixed number
The improper fraction of third mixed number
Multiply
Multiply the numerators
Multiply the denominators
Therefore, the multiplication of fractions is as follows:
The greatest common factor of
Divide numerator and denominator of fraction by
The mixed conversion of
The mixed conversion of
Thus, the multiplication of fractions is
Conclusion:
The multiplication of fractions is
Want to see more full solutions like this?
Chapter 4 Solutions
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
- [) Hwk 25 → C Hwk 27 - (MA 244-03) (SP25) IN X Answered: [) Hwk 25 4. [-/4 Poir X + https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=36606606&tags=autosave#question3706544_6 3. [-/2.85 Points] DETAILS MY NOTES LARLINALG8 7.1.021. Find the characteristic equation and the eigenvalues (and a basis for each of the corresponding eigenspaces) of the matrix. 2 -2 5 0 3 -2 0-1 2 (a) the characteristic equation (b) the eigenvalues (Enter your answers from smallest to largest.) (1, 2, 13) = ·( ) a basis for each of the corresponding eigenspaces X1 x2 = x3 = Need Help? Read It Watch It SUBMIT ANSWER 4. [-/2.85 Points] DETAILS MY NOTES LARLINALG8 7.1.041. Find the eigenvalues of the triangular or diagonal matrix. (Enter your answers as a comma-separated list.) λ= 1 0 1 045 002 Need Help? Read It ASK YOUR TEACHER PRACTICE ANOTHER ASK YOUR TEACHER PRACTICE ANOTHER illarrow_forward[) Hwk 25 4. [-/4 Points] Hwk 25 - (MA 244-03) (SP25) || X Answered: Homework#7 | bartle X + https://www.webassign.net/web/Student/Assignment-Responses/last?dep=36606604 DETAILS MY NOTES LARLINALG8 6.4.019. Use the matrix P to determine if the matrices A and A' are similar. -1 -1 12 9 '-[ ¯ ¯ ], ^ - [ _—2—2 _ ' ], ^' - [ ˜³ −10] P = 1 2 A = -20-11 A' -3-10 6 4 P-1 = Are they similar? Yes, they are similar. No, they are not similar. Need Help? Read It SUBMIT ANSWER P-1AP = 5. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.023. Suppose A is the matrix for T: R³ - → R³ relative to the standard basis. Find the diagonal matrix A' for T relative to the basis B'. A' = -1 -2 0 A = -1 0 0 ' 0 02 B' = {(−1, 1, 0), (2, 1, 0), (0, 0, 1)} ☐☐☐ ↓ ↑ Need Help? Read It Update available →] - restart now ASK YOUR T Sync and save data { Sign In ill ↑ New tab HT New window N New private window +HP ASK YOUR T Bookmarks History Downloads > > HJ Passwords Add-ons and themes HA Print... HP Save page as... HS…arrow_forwardClarification: 1. f doesn’t have REAL roots2. f is a quadratic, so a≠0arrow_forward
- [J) Hwk 25 Hwk 25 - (MA 244-03) (SP25) || X Answered: Homework#7 | bartle X + https://www.webassign.net/web/Student/Assignment-Responses/last?dep=36606604 1. [-/4 Points] DETAILS MY NOTES Find the matrix A' for T relative to the basis B'. LARLINALG8 6.4.003. T: R² → R², T(x, y) = (x + y, 4y), B' = {(−4, 1), (1, −1)} A' = Need Help? Read It Watch It SUBMIT ANSWER 2. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.007. Find the matrix A' for T relative to the basis B'. T: R³ → R³, T(x, y, z) = (x, y, z), B' = {(0, 1, 1), (1, 0, 1), (1, 1, 0)} A' = ↓ ↑ Need Help? Read It SUBMIT ANSWER 具⇧ ASK YOUR TEACHER PRACTICE ANOTHER ill ASK YOUR TEACHER PRACTICE ANOTHER 3. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.013. ASK YOUR TEACHER PRACTICE ANOTHERarrow_forwardUse Laplace transforms to solve the following heat problem: U₁ = Urr x > 0, t> 0 u(x, 0) = 10c a -X u(0,t) = 0 lim u(x,t) = 0 I7Xarrow_forwarda/ Solve the equation Laplac transfors wt = wxx W (X10)=0 w (o,t) = f (t) lim wexit) = 0 *>° t>o , to t70 848arrow_forward
- / Solve the equation Laplac transfoms:- wt = wxx WCX10) = 0 w (o,t) = f(t) lim w(x,t) = 0 X∞arrow_forwardQ/Find the Fourier sine and cosine transforms of f(x) = Xe-Xarrow_forwardQ/solve the equation Laplac transforms:- x>0, to 43 1 иху u cx,α) = f(x) и a Cort ) = • lim u(x,t) = 0 8700 و X>0 , toarrow_forward
- Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal LittellHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALElementary AlgebraAlgebraISBN:9780998625713Author:Lynn Marecek, MaryAnne Anthony-SmithPublisher:OpenStax - Rice University
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillMathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,





