Chapter 4, Problem 101P

Replace the two forces acting on the pole by a wrench. Write the force R and moment M associated with the wrench as vectors and specify the coordinates of the point P in the y-z plane through which the line of action of the wrench passes. Assume F₁ = 46 N, F₂ = 107 N, a = 1.6 m, b = 6.3 m. F₁ Answers: R=( i M = (i I Force and moment associated with wrench Coordinates of point P. (y,z) = (i F₂ T b i+ i ¡+ i i j+ i j+ ) m i k) N k) N-m

Handle forces F¡ and F2 are applied to the electric drill. Replace this force system by an equivalent resultant force and couple moment acting at point 0. Express the results in Cartesian vector form. Set F, = { 3j - 6k } N and F2 = { 9i - 4.5j - 15k } N 0.15 m- 0.25 m 0.3 m

SOLVE ASAPThe line of action of force F₁ = 388 N is passing through point A(+2,+3,+1) towards B(+5,+5, +4), while that of force F₂ = 488 N is through point C(+3,+1,−1) towards D(-2, -3, -4). Use a right-handed coordinate system.a. Determine the moment of force F₁ about the origin.b. Determine the moment of force F2 about the origin. c. Determine the magnitude of the resultant moment of forces Fi and F₂ about segment OE. Point O is the origin and point E is at (+5,+5,-3).