FUND.OF PHYSICS
FUND.OF PHYSICS
11th Edition
ISBN: 9781119306887
Author: Halliday
Publisher: WILEY
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Chapter 39, Problem 72P
To determine

To find

a) Electric potential

b) Electric potential energy of the atom (eV)

c) Kinetic energy of electron (eV)

d) Energy required to ionize the atom (eV)

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A block of mass m = 7.00 kg is released from rest from point and slides on the frictionless track shown in the figure below. (Assume h₂ = 7.80 m.) a m ha 3.20 m 2.00 m i (a) Determine the block's speed at points ® and point B ©. m/s m/s point (b) Determine the net work done by the gravitational force on the block as it moves from point J A to point
A 1.10 x 10²-g particle is released from rest at point A on the inside of a smooth hemispherical bowl of radius R R B 2R/3 (a) Calculate its gravitational potential energy at A relative to B. ] (b) Calculate its kinetic energy at B. ] (c) Calculate its speed at B. m/s (d) Calculate its potential energy at C relative to B. J (e) Calculate its kinetic energy at C. ] = 26.5 cm (figure below).
Report on the percentage errors (with uncertainty) between the value of 'k' from the F vs displacement plot and each of the values of 'k' from the period measurements. Please comment on the goodness of the results.   Value of k = Spring constant k = 50.00 N/m Each of the values of k from period measurements:  Six Measurements of time for 5 osccilations: t1 = 7.76s, t2=8.00s, t3=7.40s, t4=7.00s, t5=6.90s, t6=7.10s (t1-tavg)^2 = (7.76-7.36)^2 = 0.16%(t2-tavg)^2 =(8.00-7.36)^2 = 0.4096%(t3-tavg)^2 =(7.40-7.36)^2 = 0.0016%(t4-tavg)^2 =(7.00-7.36)^2 = 0.1296%(t5-tavg)^2 =(6.90-7.36)^2 = 0.2116%(t6-tavg)^2 =(7.10-7.36)^2 = 0.0676

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FUND.OF PHYSICS

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