FUND.OF PHYSICS(LL)-PRINT COMP-W/ACCESS
FUND.OF PHYSICS(LL)-PRINT COMP-W/ACCESS
11th Edition
ISBN: 9781119455608
Author: Halliday
Publisher: WILEY
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Chapter 39, Problem 6Q
To determine

To find:

a) Is the energy of the ground state of the trapped electron multiplied by  4, 2,12,14  or some other number?

b) Are the energies of the higher energy states multiplied by this factor or by some other factor, depending on their quantum number?

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A block of mass m = 7.00 kg is released from rest from point and slides on the frictionless track shown in the figure below. (Assume h₂ = 7.80 m.) a m ha 3.20 m 2.00 m i (a) Determine the block's speed at points ® and point B ©. m/s m/s point (b) Determine the net work done by the gravitational force on the block as it moves from point J A to point
A 1.10 x 10²-g particle is released from rest at point A on the inside of a smooth hemispherical bowl of radius R R B 2R/3 (a) Calculate its gravitational potential energy at A relative to B. ] (b) Calculate its kinetic energy at B. ] (c) Calculate its speed at B. m/s (d) Calculate its potential energy at C relative to B. J (e) Calculate its kinetic energy at C. ] = 26.5 cm (figure below).
Report on the percentage errors (with uncertainty) between the value of 'k' from the F vs displacement plot and each of the values of 'k' from the period measurements. Please comment on the goodness of the results.   Value of k = Spring constant k = 50.00 N/m Each of the values of k from period measurements:  Six Measurements of time for 5 osccilations: t1 = 7.76s, t2=8.00s, t3=7.40s, t4=7.00s, t5=6.90s, t6=7.10s (t1-tavg)^2 = (7.76-7.36)^2 = 0.16%(t2-tavg)^2 =(8.00-7.36)^2 = 0.4096%(t3-tavg)^2 =(7.40-7.36)^2 = 0.0016%(t4-tavg)^2 =(7.00-7.36)^2 = 0.1296%(t5-tavg)^2 =(6.90-7.36)^2 = 0.2116%(t6-tavg)^2 =(7.10-7.36)^2 = 0.0676

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