Chapter 39, Problem 39.89CP

(a)

To determine

To show: In perfectly inelastic collision of fast moving proton with the similar target particle, the energy available to create a product particle is given by $M{c}^2=2m_{\text{p}}{c}^2\sqrt{1+\frac{K}{2m_{\text{p}}{c}^2}}$.

(b)

To determine

To show: In the colliding beam case, the relation is $M{c}^2=2m{c}^2\left(1+\frac{1}{m{c}^2}\right)$.