a) that ψ x = D e 2 k x is solution of one dimensional Schrödinger’s equation in the region x >L. b) the physical reason behind unacceptability of ψ ( x ) , although this is mathematically acceptable.

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Answer 1

Question

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

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1.62 On a training flight, a Figure P1.62 student pilot flies from Lincoln, Nebraska, to Clarinda, Iowa, next to St. Joseph, Missouri, and then to Manhattan, Kansas (Fig. P1.62). The directions are shown relative to north: 0° is north, 90° is east, 180° is south, and 270° is west. Use the method of components to find (a) the distance she has to fly from Manhattan to get back to Lincoln, and (b) the direction (relative to north) she must fly to get there. Illustrate your solutions with a vector diagram. IOWA 147 km Lincoln 85° Clarinda 106 km 167° St. Joseph NEBRASKA Manhattan 166 km 235° S KANSAS MISSOURI

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Answer 2

Question

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Answer 6

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Answer 7

Chapter 39, Problem 21P

To determine

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

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Answer 11

Ch. 39 - Prob. 1Q Ch. 39 - Prob. 2Q Ch. 39 - Prob. 3Q Ch. 39 - Prob. 4Q Ch. 39 - Prob. 5Q Ch. 39 - Prob. 6Q Ch. 39 - Prob. 7Q Ch. 39 - Prob. 8Q Ch. 39 - Prob. 9Q Ch. 39 - Prob. 10Q

a) that ψ x = D e 2 k x is solution of one dimensional Schrödinger’s equation in the region x &gt;L. b) the physical reason behind unacceptability of ψ ( x ) , although this is mathematically acceptable.

To show: a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L. b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.

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Chapter 39 Solutions

a) that ψ x = D e 2 k x is solution of one dimensional Schrödinger’s equation in the region x >L. b) the physical reason behind unacceptability of ψ ( x ) , although this is mathematically acceptable.

To show:

a) that ψx=De2kx is solution of one dimensional Schrödinger’s equation in the region x >L.

b) the physical reason behind unacceptability of ψ(x), although this is mathematically acceptable.