Campbell Biology Plus Mastering Biology with Pearson eText - Access Card Package (11th Edition)
11th Edition
ISBN: 9780134082318
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece
Publisher: PEARSON
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Textbook Question
Chapter 38.3, Problem 3CC
WHAT IF? Ø In a few species, chloroplast genes are inherited only from sperm. How might this influence efforts to prevent transgene escape?
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Describe the similarities and differences between homologousrecombination involving sister chromatid exchange (SCE) and thatinvolving homologs. Would you expect the same types of proteinsto be involved in both processes? Explain.
Don't use Ai and chatgpt
Answer in step by step with explanation.
Mapping a new mutation on the same chromosome as the mapping genes: Scenario 1
1. If the m mutation is in a gene on the same chromosome as a and b,
as shown here, what would be the expected genotype(s) and
phenotypes of the F1 individuals?
m+b
+a+
+
m++
+ab
Scenario 1:
emk
2. If individuals from this F1 generation self-fertilize, what genotypes and phenotypes of progeny would
you expect in the F2 generation? Assume that the m, a, and b genes are all linked but you don't need to
calculate exact frequencies of each genotype/phenotype.
Parental gametes will be m++ or +ab
Recombinant metes will be m+b or +a+ if there is a crossover between a and b
Or mab and +++ if there is a crossover between m and a
The most common categories will be combinations with the parental gametes
+a+ wild-type
m+b M-only
+ab wild-type
m++ M-only
mab M-only
+++ wild-type
+a+
+a+ A-only
m+b B-only
+ab AB
m++ wild-type
mab AB
+++ wild-type
+a+ wild-type
m+b MB
mab MB
+++ wild-type
A-only
m+b wild-type
mab A-only…
Chapter 38 Solutions
Campbell Biology Plus Mastering Biology with Pearson eText - Access Card Package (11th Edition)
Ch. 38.1 - Distinguish between pollination and fertilization.Ch. 38.1 - Prob. 2CCCh. 38.1 - MAKE CONNECTIONS Does the life cycle of humans...Ch. 38.2 - What are three ways that flowering plants avoid...Ch. 38.2 - Prob. 2CCCh. 38.2 - Prob. 3CCCh. 38.3 - Compare traditional plant-breeding methods with...Ch. 38.3 - Why does Bt maize have less fumonisin than non-GM...Ch. 38.3 - WHAT IF? In a few species, chloroplast genes are...Ch. 38 - What changes occur to the four types of floral...
Ch. 38 - Prob. 38.2CRCh. 38 - Prob. 38.3CRCh. 38 - A fruit is (A) a mature ovary. (B) a mature ovule....Ch. 38 - Prob. 2TYUCh. 38 - Double fertilization means that (A) flowers must...Ch. 38 - Prob. 4TYUCh. 38 - Prob. 5TYUCh. 38 - A small flower with green petals is most likely...Ch. 38 - The black dots that cover strawberries are...Ch. 38 - DRAW IT Draw and label the parts of a flower.Ch. 38 - Prob. 9TYUCh. 38 - Prob. 10TYUCh. 38 - SCIENCE, TECHNOLOGY, AND SOCIETY Humans have...Ch. 38 - WRITE ABOUT A THEME: ORGANIZATION In a short essay...Ch. 38 - SYNTHESIZE YOUR KNOWLEDGE This colorized SEM shows...
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- The mitochondrial genome of Chlamydomonas contains the lowest number of genes, 12, of all the species of green algae. However, only 7 proteins are produced inside these mitochondria. Which of the following statements is the best explanation for why only 7 proteins are made from the 12 genes In Chlamydomonas mitochondria? OA Five of the genes are redundant; another copy is expressed from the nuclear genome.. OB. Five of the genes are nonfunctional "pseudogenes". OC Five of the genes are transcribed, but not translated. OD. Five of the genes are coding for proteins that are translated in the cytoplasm. Reset Selectionarrow_forwardVISUALIZE Use two different colors to depict the unduplicated chromosomes of species C with larger chromosomes (2n = 8) and species D with slightly smaller chromosomes (2n = 10), and of their F1 hybrid. Is the hybrid likely to be fertile?arrow_forwardWould you simply answer the question for me, i saw many answers for it but still not sure. The flower color of genetically identical hemp plants (clones) is purple when the flowers develop under cold environment (30 °C). Describe in detail a molecular mechanism that could explain how these two groups of genetically identical plants differ in their gene expressions to produce different flower colors?arrow_forward
- Can someone help with this question?arrow_forwardA mutation that increases the reach of Aurora B where Ndc80 can be modified under tension would lead to: Select one: O a. chromosomes strongly bound to kinetochore microtubules, even when not yet bivalently attached O b. chromosomes strongly bound to kinetochore microtubules, even when bivalently attached O c. chromosomes weakly bound to kinetochore microtubules, even when not yet bivalently attached O d. chromosomes weakly bound to kinetochore microtubules, even when bivalently attachedarrow_forwardVhich statement best explains why so many variations in coat colors exist? O Each coat color is the result of mutations that take place after the horse is born. The recombination of genes during meiosis results in offspring that exhibit a variety of coat colors. O Varying gene expression after fertilization leads to a variety of coat colors. O Recombination during mitosis leads to the expression of different coat colors as the horse develops.arrow_forward
- I breed a red flower to a blue flower. What would I get if the red and blue genes in these flowers were:A) incomplete dominance B) codominance 2. What are the two purposes of the membrane?3. What is the difference between passive and active transport? 4. What kind of stem cells are pluripotent?arrow_forwardExplain the likely evolutionary origin of mitochondrial and chloroplast genomes. How have the sizes of the mitochondrial and chloroplast genomes changed since their origin? How has thisoccurred?arrow_forward. In the plant Arabidopsis thaliana, a geneticist is interested in the development of trichomes (small projections). A large screen turns up two mutant plants (A and B) that have no trichomes, and these mutants seem to be potentially useful in studying trichome development. (If they were determined by single-gene mutations, then finding the normal and abnormal functions of these genes would be instructive.) Each plant is crossed with wild type; in both cases, the next generation (F1) had normal trichomes. When F1 plants were selfed, the resulting F2’s were as follows: F2 from mutant A: 602 normal; 198 no trichomes F2 from mutant B: 267 normal; 93 no trichomesa. What do these results show? Include proposed genotypes of all plants in your answer. b. Under your explanation to part a, is it possible to confidently predict the F1 from crossing the original mutant A with the original mutant B?arrow_forward
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