Explanation 1) Concept: We find the total energy of the electron and the wave number in region 1. Finding the value of b and substituting in transmission coeffient formula, we can find the transmission coefficient of the barrier. Taking the product of transmission coefficient and the initial current of region 1, we can find the transmitted current in region 2. 2) Formula: i) E = 1 2 m v 2 ii) k = 2 π λ iii) T = e - 2 b L iv) b = 8 π 2 m U b - E h 2 v) T = I t I 0 3) Given: i) Speed of electrons v = 1.200 × 10 3 m s ii) Current I 0 = 9.000 m A iii) Height of potential barrier U b = - 4.719 μ V iv) Thickness L = 200.0 n m 4) Calculations: The energy of the electron in the region 1 is E = K + P . E E = 1 2 m v 2 + 0 E = 1 2 ( 9.11 × 10 - 31 k g ) 1.2 × 10 3 m s 2 E = 6.56 × 10 - 25 J E = 4.0995 μ e V The wave number in region 1 is k = 2 π λ The de-Broglie wavelength is λ = h p k = 2 π p h The linear momentum p = m v k = 2 π m v h k = 2 π ( 9.11 × 10 - 31 k g ) ( 1200 m s ) 6

Fundamentals Of Physics 11e Student Solutions Manual

11th Edition

ISBN: 9781119455127

Author: David Halliday

Publisher: WILEY

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Chapter 38, Problem 78P

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Transmitted current.

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Chapter 38, Problem 77P

Chapter 38, Problem 79P

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Chapter 38 Solutions

Fundamentals Of Physics 11e Student Solutions Manual

Ch. 38 - Prob. 1Q Ch. 38 - Prob. 2Q Ch. 38 - Prob. 3Q Ch. 38 - Prob. 4Q Ch. 38 - Prob. 5Q Ch. 38 - Prob. 6Q Ch. 38 - Prob. 7Q Ch. 38 - Prob. 8Q Ch. 38 - Prob. 9Q Ch. 38 - Prob. 10Q

Ch. 38 - Prob. 11Q Ch. 38 - Prob. 12Q Ch. 38 - Prob. 13Q Ch. 38 - Prob. 14Q Ch. 38 - Prob. 15Q Ch. 38 - Prob. 16Q Ch. 38 - Prob. 1P Ch. 38 - Prob. 2P Ch. 38 - Prob. 3P Ch. 38 - Prob. 4P Ch. 38 - Prob. 5P Ch. 38 - Prob. 6P Ch. 38 - Prob. 7P Ch. 38 - Prob. 8P Ch. 38 - Prob. 9P Ch. 38 - Prob. 10P Ch. 38 - Prob. 11P Ch. 38 - Prob. 12P Ch. 38 - Prob. 13P Ch. 38 - Prob. 14P Ch. 38 - Prob. 15P Ch. 38 - Prob. 16P Ch. 38 - Prob. 17P Ch. 38 - Prob. 18P Ch. 38 - Prob. 19P Ch. 38 - Prob. 20P Ch. 38 - Prob. 21P Ch. 38 - Prob. 22P Ch. 38 - Prob. 23P Ch. 38 - Prob. 24P Ch. 38 - Prob. 25P Ch. 38 - Prob. 26P Ch. 38 - Prob. 27P Ch. 38 - Prob. 28P Ch. 38 - Prob. 29P Ch. 38 - Prob. 30P Ch. 38 - Prob. 31P Ch. 38 - Prob. 32P Ch. 38 - Prob. 33P Ch. 38 - Prob. 34P Ch. 38 - Prob. 35P Ch. 38 - Prob. 36P Ch. 38 - Prob. 37P Ch. 38 - Prob. 38P Ch. 38 - Prob. 39P Ch. 38 - Prob. 40P Ch. 38 - Prob. 41P Ch. 38 - Prob. 42P Ch. 38 - Prob. 43P Ch. 38 - Prob. 44P Ch. 38 - Prob. 45P Ch. 38 - Prob. 46P Ch. 38 - Prob. 47P Ch. 38 - Prob. 48P Ch. 38 - Prob. 49P Ch. 38 - Prob. 50P Ch. 38 - Prob. 51P Ch. 38 - Prob. 52P Ch. 38 - Prob. 53P Ch. 38 - Prob. 54P Ch. 38 - Prob. 55P Ch. 38 - Prob. 56P Ch. 38 - Prob. 57P Ch. 38 - Prob. 58P Ch. 38 - Prob. 59P Ch. 38 - Prob. 60P Ch. 38 - Prob. 61P Ch. 38 - Prob. 62P Ch. 38 - Prob. 63P Ch. 38 - Prob. 64P Ch. 38 - Prob. 65P Ch. 38 - Prob. 66P Ch. 38 - Prob. 67P Ch. 38 - Prob. 68P Ch. 38 - Prob. 69P Ch. 38 - Prob. 70P Ch. 38 - Prob. 71P Ch. 38 - Prob. 72P Ch. 38 - Prob. 73P Ch. 38 - Prob. 74P Ch. 38 - Prob. 75P Ch. 38 - Prob. 76P Ch. 38 - Prob. 77P Ch. 38 - Prob. 78P Ch. 38 - Prob. 79P Ch. 38 - Prob. 80P Ch. 38 - Prob. 81P Ch. 38 - Prob. 82P Ch. 38 - Prob. 83P Ch. 38 - Prob. 84P Ch. 38 - Prob. 85P Ch. 38 - Prob. 86P Ch. 38 - Prob. 87P Ch. 38 - Prob. 88P Ch. 38 - Prob. 89P Ch. 38 - Prob. 90P

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Transmitted current.

Solution Summary: The author calculates the energy of the electron in the region 1 and the wave number in region 1.

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To find: Transmitted current.

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Chapter 38 Solutions

To find:

Transmitted current.