Essential University Physics: Volume 2 (3rd Edition)
3rd Edition
ISBN: 9780321976420
Author: Richard Wolfson
Publisher: PEARSON
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Chapter 38, Problem 62P
To determine
The initial activity concentration of oxygen-15.
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The charred bones of a sloth in a cave in Chile represent the earliest evidence of human presence at the southern tip of South America. A sample of the bone has a specific activity of 5.22 disintegrations per minute per gram of carbon (d/min*g). If the 12Cy14C ratio for living organisms results in a specific activity of 15.3 d/min*g, how old are the bones (t1/2 of 14C = 5730 yr)?
To determine the wear of an automobile engine, a steel compression ring is placed in a nuclear reactor, where it becomes neutron activated because of the formation of 59Fe(t1/2 = 44.5 days, β-). The activity of the ring when placed in the engine is 4.0 x 105 Bq. Over the next 60 days, the car is driven 100,000 km on a test track. The engine oil is extracted, and the activity rate of the oil is measured to be 512 β - /min. What fraction of the ring was worn off during the test?
A small region of a cancer patient’s brain is exposed for 24.0 min to 475 Bq of radioactivity from ⁶⁰Co for treatment of atumor. If the brain mass exposed is 1.858 g and β⁻ each particle emitted has an energy of 5.05X10⁻¹⁴J, what is the dose in rads?
Chapter 38 Solutions
Essential University Physics: Volume 2 (3rd Edition)
Ch. 38.1 - Prob. 38.1GICh. 38.2 - Prob. 38.2GICh. 38.3 - Prob. 38.3GICh. 38.4 - Prob. 38.4GICh. 38.5 - Prob. 38.5GICh. 38 - Prob. 1FTDCh. 38 - Prob. 2FTDCh. 38 - Prob. 3FTDCh. 38 - Prob. 4FTDCh. 38 - Prob. 5FTD
Ch. 38 - Why are iodine-131 and strontium-90 particularly...Ch. 38 - Prob. 7FTDCh. 38 - Prob. 8FTDCh. 38 - Prob. 9FTDCh. 38 - Prob. 10FTDCh. 38 - Prob. 11FTDCh. 38 - Prob. 12FTDCh. 38 - Prob. 13FTDCh. 38 - Prob. 14FTDCh. 38 - Explain the different approaches to the Lawson...Ch. 38 - Prob. 16FTDCh. 38 - Three radon isotopes have 125, 134, and 136...Ch. 38 - Prob. 18ECh. 38 - Prob. 19ECh. 38 - Prob. 20ECh. 38 - Prob. 21ECh. 38 - How many half-lives will it take for the activity...Ch. 38 - Prob. 23ECh. 38 - Prob. 24ECh. 38 - Prob. 25ECh. 38 - Prob. 26ECh. 38 - Prob. 27ECh. 38 - Prob. 28ECh. 38 - Use Fig. 38.9 to estimate the mass defect in...Ch. 38 - Find the total binding energy of oxygen-16, given...Ch. 38 - Determine the nuclear mass of nickel-60, given...Ch. 38 - Prob. 32ECh. 38 - Prob. 33ECh. 38 - Prob. 34ECh. 38 - Prob. 35ECh. 38 - Prob. 36ECh. 38 - Prob. 37ECh. 38 - Prob. 38ECh. 38 - Prob. 39ECh. 38 - Prob. 40ECh. 38 - Prob. 41ECh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Iron-56, with nuclear mass 55.9206 u, is among the...Ch. 38 - Prob. 46PCh. 38 - As a geologist, youre assessing the feasibility of...Ch. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Nitrogen-13 is a 9.97-min-half-lifc isotope used...Ch. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53PCh. 38 - Prob. 54PCh. 38 - The table below lists reported levels of...Ch. 38 - Prob. 56PCh. 38 - Analysis of a Moon rock shows that 82% of its...Ch. 38 - Prob. 58PCh. 38 - Prob. 59PCh. 38 - Today, uranium-235 comprises only 0.72% of natural...Ch. 38 - Prob. 61PCh. 38 - Prob. 62PCh. 38 - Prob. 63PCh. 38 - Prob. 64PCh. 38 - Prob. 65PCh. 38 - Prob. 66PCh. 38 - Prob. 67PCh. 38 - Prob. 68PCh. 38 - Prob. 69PCh. 38 - Prob. 70PCh. 38 - Prob. 71PCh. 38 - Prob. 72PCh. 38 - Prob. 73PCh. 38 - Prob. 74PCh. 38 - Bismuth-209 and chromium-54 combine to form a...Ch. 38 - Prob. 76PCh. 38 - Prob. 77PCh. 38 - Prob. 78PCh. 38 - Prob. 79PCh. 38 - Prob. 80PCh. 38 - Prob. 81PCh. 38 - Prob. 82PCh. 38 - Prob. 83PCh. 38 - Prob. 84PCh. 38 - Prob. 85PCh. 38 - Prob. 86PPCh. 38 - Prob. 87PPCh. 38 - Prob. 88PPCh. 38 - Prob. 89PP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Calculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forwardData from the appendices and the periodic table may be needed for these problems. Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.arrow_forwardA beam of 168MeV nitrogen nuclei is used for cancer therapy. If this beam is directed onto a 0.200kg tumor and gives it a 2.00Sv dose, how many nitrogen nuclei were stopped? (Use an RBE of 20 for heavy ions.)arrow_forward
- Data from the appendices and the periodic table may be needed for these problems. A 60Co source is labeled 4.00 mCi, but its present activity is found to be 1.85107Bq. (a) What is the present activity in mCi? (b) How long ago did it actually have a 4.00—mCi activity?arrow_forward(a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forward(a) Find the total energy released in MeV in each carbon cycle (elaborated in the above problem) including the annihilation energy. (b) How does this compare with the protonproton cycle output?arrow_forward
- (a) How many 239Pu nuclei must fission to produce a 20.0kT yield, assuming 200 MeV per fission? (b) What is the mass of this much 239Pu?arrow_forwardWhat is the mass of 60Co in a cancer therapy transillumination unit containing 5.00 kCi of 60Co?arrow_forward(a) Calculate the energy released in the neutron- Induced fission reaction n+235U92Kr+142Ba+2n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward
- (a) Calculate the energy released in the neutron- induced fission n+238U96Sr+140Xe+3n , given m(96Sr)=95.921750uand m(140Xe)=139.92164 . This result is about 6 MeV greater than the result for spontaneous fission. Why? Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forwardThe body of a stone-age man was found in a glacier in 1997. The body was dated using radiocarbon dating. Recall that t1/2 for 14C is 5840 yrs and R0 = 0.25 Bq for 1 g of 14C in a living organism. Material found within the body had a 14C activity R = 0.133 Bq per gram of carbon. What is the age ( in years) of the body?arrow_forwardA living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22011) contains 30.0 mg of carbon. When the sample is placed inside a shielded beta counter with 86% counting efficiency, 833 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample in the nearest year (1 yr ~ 3.156 × 10' s).arrow_forward
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