Explanation 1) Concept: Using Eq.38-24 and the given values, we can find the resulting wave function and we can describe its nature. Taking square of the absolute value of ψ x and solving as a complex number, we can find how, if at all, Fig.38-13 would be altered. 2) Formulas: i) From Eq.38-24, we have ψ x = A e i k x + B e - i k x ii) From Eq.38-25, the time dependent wave function is ψ x , t = ψ x e - i ω t 3) Given: i) Put A = 0 in Eq.38-24. ii) Relabeled B as ψ 0 . iii) Fig.38-13. 4) Calculations: a) From Eq.38-24, we have ψ x = A e i k x + B e - i k x From the given, we get ψ x = ψ 0 e - i k x The time dependent wave function is ψ x , t = ψ x e - i ω t Substituting, ψ x , we get ψ x , t = ψ 0 e - i k x e - i ω t ψ x , t = ψ 0 e - i k x - ω t This function describes a plane matter wave travelling in the negative x direction

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Question

Chapter 38, Problem 60P

To determine

To find:

a) The resulting wave function.

b) How, if at all, would Fig.38-13 be altered?

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Chapter 38, Problem 59P

Chapter 38, Problem 61P

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