Explanation 1) Concept: We know that the number of photons emitted per unit time ( R ) is the ratio of power of laser source to the photon energy, and current due to ejected electron is a product of R and P s . Using this and the given information, we can find the current of electrons ejected. 2) Formula: i) Current due to electron, i = n e / s e c where n is number of electrons and e is the charge on electron ii) Rate of emission of photons R = d N d t = d d t E s o u r c e ϵ 3) Given: i) Work function of Cesium, ϕ = 1.8 e V ii) Fractional efficiency of cesium surface is η = 1.0 × 10 - 16 iii) Wavelength of incident light, λ = 600 n m iv) Power of light source (LASER), P s = 2.0 m W = 2.0 × 10 - 3 W 4) Calculations: We have relation for rate of emission of photons as below: R = d N d t = d d t E s o u r c e ϵ = E s o u r c e t ϵ = P s ϵ where ϵ is energy of photon and P s is power delivered by light source; also N is the number of photons emitted

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ISBN: 9781119460138

Author: Halliday

Publisher: WILEY

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Chapter 38, Problem 20P

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Current of electrons ejected from the cesium surface.

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Chapter 38, Problem 19P

Chapter 38, Problem 21P

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Chapter 38 Solutions

FUNDAMENTALS OF PHYSICS: EXTENDED (LL)

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