Thedischarge of charged electroscope by shining in ultraviolet light

Question

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Answer 1

Question

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

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Answer 2

Question

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

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Answer 3

Question

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

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Answer 4

Question

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

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Answer 5

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Answer 6

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

Answer 7

Chapter 38, Problem 1CQ

(a).

To determine

Thedischarge of charged electroscope by shining in ultraviolet light

Answer 8

(a).

Expert Solution

Answer to Problem 1CQ

Solution: The discharge of charged electroscope by shining in ultraviolet light is due to Photoelectric effect.

Answer 9

(a).

Expert Solution

Answer 10

(a).

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given Info: Negatively charged electroscope
Ultraviolet light

The discharge is due to Photoelectric effect. According to Einstein’s photoelectric equation, each photon in incident light will bring an electron on top of metal surface (which is called as work function) and the leftover energy of light is given to photo electrons as kinetic energy. In the present case, incident light energy of ultraviolet should be greater than work function of negatively charged electroscope and this causes discharge.

Conclusion:

Thedischarge of charged electroscope by shining in ultraviolet lightis due to Photoelectric effect.

Answer 13

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Answer 14

(b).

To determine

Thedischarge of uncharged electroscope by shining in ultraviolet light may not make positively charged electroscope.

Answer 15

(b).

Expert Solution

Answer to Problem 1CQ

Solution:

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non -discharge of electroscope. Hence, the electroscope may not become positive.

Answer 16

(b).

Expert Solution

Answer 17

(b).

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given Info: Uncharged electroscope
Ultraviolet light

In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.

Conclusion:
In the present case of uncharged electroscope, incident light energy of ultraviolet should be lesser than work function and this cause non discharge of electroscope. Hence, the electroscope may not become positive.