Mathematics for Machine Technology
Mathematics for Machine Technology
7th Edition
ISBN: 9781133281450
Author: John C. Peterson, Robert D. Smith
Publisher: Cengage Learning
bartleby

Videos

Question
Book Icon
Chapter 38, Problem 13A
To determine

(a)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  24

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  4×6=24 {using the multiplication principle}

To determine

(b)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  24

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  4×6=24 {using the multiplication principle.}

To determine

(c)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  30

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  3×10=30 {using the multiplication principle.}

To determine

(d)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  30

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  3×10=30 {using the multiplication principle.}

To determine

(e)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  35

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  5×7=35 {using the multiplication principle.}

To determine

(f)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  28

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  2×14=28 {using the multiplication principle.}

To determine

(g)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  0×16=0 {using the multiplication principle.}

To determine

(h)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  32.5

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  5×6.5=32.5 {using the multiplication principle.}

To determine

(i)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0.32

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  3.2×0.1=0.32 {using the multiplication principle.}

To determine

(j)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0.036

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  0.06×0.60=0.036 {using the multiplication principle.}

To determine

(k)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  92

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  112×34=92 {using the multiplication principle.}

To determine

(l)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  14×0=0

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  14×0=0 {using the multiplication principle.}

To determine

(m)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  2×4=8

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  2×4=8 {using the multiplication principle.}

To determine

(n)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  2×4=8

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  2×4=8 {using the multiplication principle.}

To determine

(o)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  8×4×0×3×1=0

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  8×4×0×3×1=0 {using the multiplication principle.}

To determine

(p)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  7350.488

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  3.86×2.1×27.85×32.56=7350.488 {using the multiplication principle.}

To determine

(q)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  10.6

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  8×2.65×0.5×1=10.6 {using the multiplication principle.}

To determine

(s)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0.384

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  4.03×0.25×3×0.127=0.384 {using the multiplication principle.}

To determine

(r)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0.2205

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  6.3×0.35×2×1×0.05=0.2205 {using the multiplication principle.}

To determine

(t)

To solve the expression using the multiplication principle.

Expert Solution
Check Mark

Answer to Problem 13A

  0.3

Explanation of Solution

Given information:

The given expression is problem.

Calculation:

By solving this expression.

  0.03×100×0.10=0.3 {using the multiplication principle.}

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
5) State any theorems that you use in determining your solution. a) Suppose you are given a model with two explanatory variables such that: Yi = a +ẞ1x1 + ẞ2x2i + Ui, i = 1, 2, ... n Using partial differentiation derive expressions for the intercept and slope coefficients for the model above. [25 marks] b) A production function is specified as: Yi = α + B₁x1i + ẞ2x2i + Ui, i = 1, 2, ... n, u₁~N(0,σ²) where: y = log(output), x₁ = log(labor input), x2 = log(capital input) The results are as follows: x₁ = 10, x2 = 5, ỹ = 12, S11 = 12, S12= 8, S22 = 12, S₁y = 10, = 8, Syy = 10, S2y n = 23 (individual firms) i) Compute values for the intercept, the slope coefficients and σ². [20 marks] ii) Show that SE (B₁) = 0.102. [15 marks] iii) Test the hypotheses: ẞ1 = 1 and B2 = 0, separately at the 5% significance level. You may take without calculation that SE (a) = 0.78 and SE (B2) = 0.102 [20 marks] iv) Find a 95% confidence interval for the estimate ẞ2. [20 marks]
Page < 2 of 2 - ZOOM + The set of all 3 x 3 upper triangular matrices 6) Determine whether each of the following sets, together with the standard operations, is a vector space. If it is, then simply write 'Vector space'. You do not have to prove all ten vector space axioms. If it is not, then identify one of the ten vector space axioms with its number in the attached sheet that fails and also show that how it fails. a) The set of all polynomials of degree four or less. b) The set of all 2 x 2 singular matrices. c) The set {(x, y) : x ≥ 0, y is a real number}. d) C[0,1], the set of all continuous functions defined on the interval [0,1]. 7) Given u = (-2,1,1) and v = (4,2,0) are two vectors in R³-space. Find u xv and show that it is orthogonal to both u and v. 8) a) Find the equation of the least squares regression line for the data points below. (-2,0), (0,2), (2,2) b) Graph the points and the line that you found from a) on the same Cartesian coordinate plane.
Page < 1 of 2 - ZOOM + 1) a) Find a matrix P such that PT AP orthogonally diagonalizes the following matrix A. = [{² 1] A = b) Verify that PT AP gives the correct diagonal form. 2 01 -2 3 2) Given the following matrices A = -1 0 1] an and B = 0 1 -3 2 find the following matrices: a) (AB) b) (BA)T 3) Find the inverse of the following matrix A using Gauss-Jordan elimination or adjoint of the matrix and check the correctness of your answer (Hint: AA¯¹ = I). [1 1 1 A = 3 5 4 L3 6 5 4) Solve the following system of linear equations using any one of Cramer's Rule, Gaussian Elimination, Gauss-Jordan Elimination or Inverse Matrix methods and check the correctness of your answer. 4x-y-z=1 2x + 2y + 3z = 10 5x-2y-2z = -1 5) a) Describe the zero vector and the additive inverse of a vector in the vector space, M3,3. b) Determine if the following set S is a subspace of M3,3 with the standard operations. Show all appropriate supporting work.

Chapter 38 Solutions

Mathematics for Machine Technology

Knowledge Booster
Background pattern image
Advanced Math
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Mathematics For Machine Technology
Advanced Math
ISBN:9781337798310
Author:Peterson, John.
Publisher:Cengage Learning,
Text book image
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
Text book image
Elementary Algebra
Algebra
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:OpenStax - Rice University
Text book image
College Algebra
Algebra
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:Cengage Learning
Text book image
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Text book image
Intermediate Algebra
Algebra
ISBN:9780998625720
Author:Lynn Marecek
Publisher:OpenStax College
An Introduction to Area | Teaching Maths | EasyTeaching; Author: EasyTeaching;https://www.youtube.com/watch?v=_uKKl8R1xBM;License: Standard YouTube License, CC-BY
Area of a Rectangle, Triangle, Circle & Sector, Trapezoid, Square, Parallelogram, Rhombus, Geometry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=JnLDmw3bbuw;License: Standard YouTube License, CC-BY