Biology (MindTap Course List)
11th Edition
ISBN: 9781337392938
Author: Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher: Cengage Learning
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Chapter 37.5, Problem 11LO
Summary Introduction
To define: Apomixis.
Concept introduction: Flower is a reproductive part of the modified thick shoot of an
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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin
Chapter 37 Solutions
Biology (MindTap Course List)
Ch. 37.1 - Prob. 1LOCh. 37.1 - Prob. 2LOCh. 37.1 - Prob. 1CCh. 37.1 - Prob. 2CCh. 37.1 - Prob. 3CCh. 37.1 - Prob. 4CCh. 37.2 - Compare the evolutionary adaptations that...Ch. 37.2 - Prob. 4LOCh. 37.2 - Prob. 1CCh. 37.2 - Prob. 2C
Ch. 37.2 - Give three examples in which the relationship of a...Ch. 37.3 - Prob. 5LOCh. 37.3 - Prob. 6LOCh. 37.3 - Explain the relationships among ovules, ovaries,...Ch. 37.3 - Distinguish among simple, aggregate, multiple, and...Ch. 37.3 - Prob. 1CCh. 37.3 - What are the main stages of eudicot embryonic...Ch. 37.3 - Prob. 3CCh. 37.3 - Prob. 4CCh. 37.3 - What are some characteristics of animal-dispersed...Ch. 37.4 - Prob. 9LOCh. 37.4 - Prob. 1CCh. 37.4 - How does early seedling development differ in...Ch. 37.5 - Explain how the following structures may be used...Ch. 37.5 - Prob. 11LOCh. 37.5 - How are rhizomes and tubers involved in asexual...Ch. 37.5 - Prob. 2CCh. 37.5 - Prob. 3CCh. 37.6 - Prob. 12LOCh. 37.6 - Prob. 1CCh. 37.6 - Prob. 2CCh. 37 - The normal order of whorls from the flowers...Ch. 37 - Prob. 2TYUCh. 37 - Prob. 3TYUCh. 37 - Prob. 4TYUCh. 37 - The process of _______________ in flowering plants...Ch. 37 - The nutritive tissue in the seeds of flowering...Ch. 37 - Prob. 7TYUCh. 37 - In plants that lack endosperm in their mature...Ch. 37 - Prob. 9TYUCh. 37 - A horizontal underground stem that may or may not...Ch. 37 - Place the following events in the correct order:...Ch. 37 - Prob. 12TYUCh. 37 - Prob. 13TYUCh. 37 - Prob. 14TYUCh. 37 - Which type of reproduction, sexual or asexual,...Ch. 37 - Prob. 16TYUCh. 37 - Prob. 17TYU
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- How many types of reactions can an enzyme perform?arrow_forwardYour goal is to produce black seeds resistant to mold. So you make the same cross again (between a homozygous black seeded, mold susceptible parent and a homozygous white seeded and mold resistant parent), and, again, advance progeny by SSD to create 100 F10 generation plants. Based on the information you obtained from your first crossing experiment (Question #4), how many F10 plants would you expect to have black seeds and be resistant to mold? Assume that a toxin produced by the mold fungus has been isolated. Only mold resistant seeds will germinate in the presence of the toxin. Could you use this toxin screening procedure to have segregation distortion work in your favor in the F2 generation? Explain your answer. Info from Question 4 a. P Locus (Seed Color): Hypothesis: The null hypothesis (H₀) is that seed color is controlled by alleles at a single locus. Observed Data: Total white seeds: 45 (resistant plants) + 6 (susceptible plants) = 51 Total black seeds: 7 (resistant…arrow_forward10. Consider the following enzyme and its substrate where the "+" and "-" indicate cations and anions, respectively. Explain which of the following inhibitors could inhibit this enzyme? Which type of inhibitor would it be and why? (Video 5-2) Substrate Enzyme Potential inhibitorsarrow_forward
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