Chapter 37, Problem 1SQ

To determine

Choose the correct option to find the synchronous speed of a stator winding of a wound rotor containing six poles per phase.

Answer to Problem 1SQ

The correct option is $\text{d}.1200\text{RPM}$.

Explanation of Solution

Given data:

The number of poles per phase $\left(p\right)$ is $6$.

The frequency of the motor $\left(f\right)$ is $60\text{Hz}$.

Formula used:

Write the general expression to find the synchronous speed.

$N_s=\frac{120f}{p}$ (1)

Here,

$f$ is the frequency of the motor,

$p$ is the number of poles per phase.

Calculation:

Substitute $60\text{Hz}$ for $f$, and $6$ for $p$ in Equation (1).

$\begin{array}{c}{N}_s=\frac{120\left(60\text{Hz}\right)}{6}\\ =1200\text{RPM}\end{array}$

Therefore, the synchronous speed is $1200\text{RPM}$.

Conclusion:

Thus, the correct option is $\text{d}.1200\text{RPM}$.