EBK MINDTAP FOR HERMAN'S UNDERSTANDING
4th Edition
ISBN: 9781337798761
Author: Herman
Publisher: VST
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Question
Chapter 37, Problem 12RQ
To determine
The size of the conductor used to supply the motors.
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Q: Consider the square of Figure below.The left face is maintained at 100°C and the top
face at 500°C, while the other two faces are exposed to an environment at1 00°C, h=10
W/m². C and k=10 W/m.°C. The block is 1 m square. Compute the temperature of the
various nodes as indicated in Figure below and the heat flows at the boundaries.
T= 500°C
Alt
Explain to me in detail how to
calculate the matrix in the Casio
calculator type (fx-991ES plus)
T= 100°C
1
2
4
7
1 m-
3
1 m
5
6
T=
100°C
8
9
Which of the following sequences converge and which diverge?
1)
a₁ = 2+(0.1)"
1-2n
2)
a =
1+2n
1/n
3
16) a =
n
In n
17) an =
n
1/n
1-5n4
3)
an
=
n² +8n³
18) an
=
√4" n
n² -2n+1
n!
20) a =
4)
an
=
106
5)
n-1
a₁ =1+(-1)"
n+1
a-(+) (1-4)
6)
=
7)
a =
2n
(-1)"+1
2n-1
21) an
=
n
-A"
1/(Inn)
3n+1
22) a =
3n-1
1/n
x"
23) a =
, x>0
2n+1
3" x 6"
24) a =
2™" xn!
2n
8)
a =
n+1
πT
1
9)
a„ = sin
+-
2
n
sin n
10) an =
n
25) a = tanh(n)
26) a =
2n-1
27) a = tan(n)
1
-sin
n
n
11) a =
2"
28) an
==
"
1
+
2"
In(n+1)
12) a =
n
(In n) 200
29) a =
n
13) a = 8/n
14) a 1+
=(1+²)"
15) an
7
n
= 10n
30) an-√√n²-n
1"1
31) adx
nix
A steel alloy contains 95.7 wt% Fe, 4.0 wt% W,
and 0.3 wt% C.
Chapter 37 Solutions
EBK MINDTAP FOR HERMAN'S UNDERSTANDING
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- b. A horizontal cantilever of effective length 3a, carries two concentrated loads W at a distance a from the fixed end and W' at a distance a from the free end. Obtain a formula for the maximum deflection due to this loading using Mohr's method. If the cantilever is 250 mm by 150mm steel I beam, 3 m long having a second moment of area I as 8500 cm4, determine W and W'to give a maximum deflection of 6 mm when the maximum stress due to bending is 90 Mpa. Take Young's modulus of material E as 185 Gpa.arrow_forwardWhich of the following sequences converge and which diverge? 1/n 1) a₁ = 2+(0.1)" 3 16) a = n 1-2n 2) a = In n 1+2n 17) an = 1/n n 1-5n4 3) an = n² +8n³ 18) an = √4" n n! n² -2n+1 20) a = 4) an = 106 5) n-1 a₁ =1+(-1)" n+1 a-(+) (1-4) 6) = 7) a = 2n (-1)"+1 2n-1 21) an = n -A" 1/(Inn) 3n+1 22) a = 3n-1 1/n x" 23) a = , x>0 2n+1 3" x 6" 24) a = 2™" xn! 2n 8) a = n+1 πT 1 9) a„ = sin +- 2 n sin n 10) an = n 25) a = tanh(n) 26) a = 2n-1 27) a = tan(n) 1 -sin n n 11) a = 2" 28) an == " 1 + 2" In(n+1) 12) a = n (In n) 200 29) a = n 13) a = 8/n 14) a 1+ =(1+²)" 15) an 7 n = 10n 30) an-√√n²-n 1"1 31) adx nixarrow_forwardCalculate the angle of incidence of beam radiation on a collector located at (Latitude 17.40S) on June 15 at 1030hrs solar time. The collector is tilted at an angle of 200, with a surface azimuth angle of 150.arrow_forward
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