Explanation Given: g ( x ) = { x 2 sin 1 x x ≠ 0 0 x = 0 Key concepts applied: Squeeze theorem The Squeeze Principle is used on limit problems where the usual algebraic methods (factoring, conjugation, algebraic manipulation, etc.) are not effective. However, it requires that we are able to “squeeze” the problem in between two other simpler functions whose limits are easily computable and equal. Assume that functions f , g , and h satisfy g ( x ) ≤ f ( x ) ≤ h ( x ) and lim x → A g ( x ) = L = lim x → A h ( x ) Then lim x → A f ( x ) = L Using the limit definition, we have g ' ( 0 ) = lim h → 0 g ( 0 + h ) − g ( 0 ) h = lim h → 0

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Question

Chapter 3.7, Problem 110E

To determine

The given statement using the limit definition

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Chapter 3.7, Problem 109E

Chapter 3.7, Problem 111E

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Use the limit definition of the derivative to show that the derivative does not exist at x = a for the function. (9, x< 9 f(x) = x = 9 x, x 2 9' f(x) – 9 lim X - 9 f(x) – 9 lim x - 9

let f(x)=4x2 +12x-2 using the definition of derivative f´(x)=limh-->0 (x+h)-f(x) /h enter the expresion needed find the derivative at x=3 f¨(x)=lim h->0 after evaluating this limits, we see that f¨(x)= f¨(x)=lim h-->0 finally the equation of the tangent line to f(x) in point lope form, where x=3 is ----------- f¨(x)= limh-->0 f(x+h)-f(x) /h equation of tangent line to f(x) at x=x0 is y=f(x0 )=f¨(x0 )(x-x0 )

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Chapter 3 Solutions

Calculus: Early Transcendentals

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Prob. 46E Ch. 3.9 - Prob. 47E Ch. 3.9 - Prob. 48E Ch. 3.9 - Prob. 49E Ch. 3.9 - Prob. 50E Ch. 3.9 - Prob. 51E Ch. 3.9 - Prob. 52E Ch. 3.9 - Prob. 53E Ch. 3.9 - Prob. 54E Ch. 3.9 - Prob. 55E Ch. 3.9 - Prob. 56E Ch. 3.9 - Prob. 57E Ch. 3.9 - Prob. 58E Ch. 3.9 - Prob. 59E Ch. 3.9 - Prob. 60E Ch. 3.9 - Prob. 61E Ch. 3.9 - Prob. 62E Ch. 3.9 - Prob. 63E Ch. 3.9 - Prob. 64E Ch. 3.9 - Prob. 65E Ch. 3.9 - Prob. 66E Ch. 3.9 - Prob. 67E Ch. 3.9 - Prob. 68E Ch. 3.9 - Prob. 69E Ch. 3.9 - Prob. 70E Ch. 3.9 - Prob. 71E Ch. 3.9 - Prob. 72E Ch. 3.9 - Prob. 73E Ch. 3.9 - Prob. 74E Ch. 3.9 - Prob. 75E Ch. 3.9 - Prob. 76E Ch. 3.9 - Prob. 77E Ch. 3.9 - Prob. 78E Ch. 3.9 - Prob. 79E Ch. 3.9 - Prob. 80E Ch. 3.9 - Prob. 81E Ch. 3.9 - Prob. 82E Ch. 3.9 - Prob. 83E Ch. 3.9 - Prob. 84E Ch. 3.9 - Prob. 85E Ch. 3.9 - Prob. 86E Ch. 3.9 - Prob. 87E Ch. 3.9 - Prob. 88E Ch. 3.10 - Prob. 1PQ Ch. 3.10 - Prob. 2PQ Ch. 3.10 - Prob. 3PQ Ch. 3.10 - Prob. 4PQ Ch. 3.10 - Prob. 5PQ Ch. 3.10 - Prob. 6PQ Ch. 3.10 - Prob. 1E Ch. 3.10 - Prob. 2E Ch. 3.10 - Prob. 3E Ch. 3.10 - Prob. 4E Ch. 3.10 - Prob. 5E Ch. 3.10 - Prob. 6E Ch. 3.10 - Prob. 7E Ch. 3.10 - Prob. 8E Ch. 3.10 - Prob. 9E Ch. 3.10 - Prob. 10E Ch. 3.10 - Prob. 11E Ch. 3.10 - Prob. 12E Ch. 3.10 - Prob. 13E Ch. 3.10 - Prob. 14E Ch. 3.10 - Prob. 15E Ch. 3.10 - Prob. 16E Ch. 3.10 - Prob. 17E Ch. 3.10 - Prob. 18E Ch. 3.10 - Prob. 19E Ch. 3.10 - Prob. 20E Ch. 3.10 - Prob. 21E Ch. 3.10 - Prob. 22E Ch. 3.10 - Prob. 23E Ch. 3.10 - Prob. 24E Ch. 3.10 - Prob. 25E Ch. 3.10 - Prob. 26E Ch. 3.10 - Prob. 27E Ch. 3.10 - Prob. 28E Ch. 3.10 - Prob. 29E Ch. 3.10 - Prob. 30E Ch. 3.10 - Prob. 31E Ch. 3.10 - Prob. 32E Ch. 3.10 - Prob. 33E Ch. 3.10 - Prob. 34E Ch. 3.10 - Prob. 35E Ch. 3.10 - Prob. 36E Ch. 3.10 - Prob. 37E Ch. 3.10 - Prob. 38E Ch. 3.10 - Prob. 39E Ch. 3.10 - Prob. 40E Ch. 3.10 - Prob. 41E Ch. 3.10 - Prob. 42E Ch. 3.10 - Prob. 43E Ch. 3.10 - Prob. 44E Ch. 3.10 - Prob. 45E Ch. 3 - Prob. 1CRE Ch. 3 - Prob. 2CRE Ch. 3 - Prob. 3CRE Ch. 3 - Prob. 4CRE Ch. 3 - Prob. 5CRE Ch. 3 - Prob. 6CRE Ch. 3 - Prob. 7CRE Ch. 3 - Prob. 8CRE Ch. 3 - Prob. 9CRE Ch. 3 - Prob. 10CRE Ch. 3 - Prob. 11CRE Ch. 3 - Prob. 12CRE Ch. 3 - Prob. 13CRE Ch. 3 - Prob. 14CRE Ch. 3 - Prob. 15CRE Ch. 3 - Prob. 16CRE Ch. 3 - Prob. 17CRE Ch. 3 - Prob. 18CRE Ch. 3 - Prob. 19CRE Ch. 3 - Prob. 20CRE Ch. 3 - Prob. 21CRE Ch. 3 - Prob. 22CRE Ch. 3 - Prob. 23CRE Ch. 3 - Prob. 24CRE Ch. 3 - Prob. 25CRE Ch. 3 - Prob. 26CRE Ch. 3 - Prob. 27CRE Ch. 3 - Prob. 28CRE Ch. 3 - Prob. 29CRE Ch. 3 - Prob. 30CRE Ch. 3 - Prob. 31CRE Ch. 3 - Prob. 32CRE Ch. 3 - Prob. 33CRE Ch. 3 - Prob. 34CRE Ch. 3 - Prob. 35CRE Ch. 3 - Prob. 36CRE Ch. 3 - Prob. 37CRE Ch. 3 - Prob. 38CRE Ch. 3 - Prob. 39CRE Ch. 3 - Prob. 40CRE Ch. 3 - Prob. 41CRE Ch. 3 - Prob. 42CRE Ch. 3 - Prob. 43CRE Ch. 3 - Prob. 44CRE Ch. 3 - Prob. 45CRE Ch. 3 - Prob. 46CRE Ch. 3 - Prob. 47CRE Ch. 3 - Prob. 48CRE Ch. 3 - Prob. 49CRE Ch. 3 - Prob. 50CRE Ch. 3 - Prob. 51CRE Ch. 3 - Prob. 52CRE Ch. 3 - Prob. 53CRE Ch. 3 - Prob. 54CRE Ch. 3 - Prob. 55CRE Ch. 3 - Prob. 56CRE Ch. 3 - Prob. 57CRE Ch. 3 - Prob. 58CRE Ch. 3 - Prob. 59CRE Ch. 3 - Prob. 60CRE Ch. 3 - Prob. 61CRE Ch. 3 - Prob. 62CRE Ch. 3 - Prob. 63CRE Ch. 3 - Prob. 64CRE Ch. 3 - Prob. 65CRE Ch. 3 - Prob. 66CRE Ch. 3 - Prob. 67CRE Ch. 3 - Prob. 68CRE Ch. 3 - Prob. 69CRE Ch. 3 - Prob. 70CRE Ch. 3 - Prob. 71CRE Ch. 3 - Prob. 72CRE Ch. 3 - Prob. 73CRE Ch. 3 - Prob. 74CRE Ch. 3 - Prob. 75CRE Ch. 3 - Prob. 76CRE Ch. 3 - Prob. 77CRE Ch. 3 - Prob. 78CRE Ch. 3 - Prob. 79CRE Ch. 3 - Prob. 80CRE Ch. 3 - Prob. 81CRE Ch. 3 - Prob. 82CRE Ch. 3 - Prob. 83CRE Ch. 3 - Prob. 84CRE Ch. 3 - Prob. 85CRE Ch. 3 - Prob. 86CRE Ch. 3 - Prob. 87CRE Ch. 3 - Prob. 88CRE Ch. 3 - Prob. 89CRE Ch. 3 - Prob. 90CRE Ch. 3 - Prob. 91CRE Ch. 3 - Prob. 92CRE Ch. 3 - Prob. 93CRE Ch. 3 - Prob. 94CRE Ch. 3 - Prob. 95CRE Ch. 3 - Prob. 96CRE Ch. 3 - Prob. 97CRE Ch. 3 - Prob. 98CRE Ch. 3 - Prob. 99CRE Ch. 3 - Prob. 100CRE Ch. 3 - Prob. 101CRE Ch. 3 - Prob. 102CRE Ch. 3 - Prob. 103CRE Ch. 3 - Prob. 104CRE Ch. 3 - Prob. 105CRE Ch. 3 - Prob. 106CRE Ch. 3 - Prob. 107CRE Ch. 3 - Prob. 108CRE Ch. 3 - Prob. 109CRE Ch. 3 - Prob. 110CRE Ch. 3 - Prob. 111CRE Ch. 3 - Prob. 112CRE Ch. 3 - Prob. 113CRE Ch. 3 - Prob. 114CRE Ch. 3 - Prob. 115CRE Ch. 3 - Prob. 116CRE Ch. 3 - Prob. 117CRE Ch. 3 - Prob. 118CRE Ch. 3 - Prob. 119CRE Ch. 3 - Prob. 120CRE

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The given statement using the limit definition

Solution Summary: The author explains that the Squeeze Principle is used on limit problems where the usual algebraic methods are not effective.

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The given statement using the limit definition

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Chapter 3 Solutions