Suppose that an object that is originally at room temperature of 32°C is placed in a freezer. The temperature T ( x ) (in °C) of the object can be approximated by the model T ( x ) = 320 x 2 + 3 x + 10 , where x is the time in hours after the object is placed in the freezer. a. What is the horizontal asymptote of the graph of this function and what does it represent in the context of this problem? b. A chemist needs a compound cooled to less than 3cC. Determine the amount of time required for the compound to cool so that its temperature is less than 5°C.
Suppose that an object that is originally at room temperature of 32°C is placed in a freezer. The temperature T ( x ) (in °C) of the object can be approximated by the model T ( x ) = 320 x 2 + 3 x + 10 , where x is the time in hours after the object is placed in the freezer. a. What is the horizontal asymptote of the graph of this function and what does it represent in the context of this problem? b. A chemist needs a compound cooled to less than 3cC. Determine the amount of time required for the compound to cool so that its temperature is less than 5°C.
Solution Summary: The author explains how the horizontal asymptote of the graph is y=0.
Suppose that an object that is originally at room temperature of 32°C is placed in a freezer. The temperature T(x) (in °C) of the object can be approximated by the model
T
(
x
)
=
320
x
2
+
3
x
+
10
, where x is the time in hours after the object is placed in the freezer.
a. What is the horizontal asymptote of the graph of this function and what does it represent in the context of this problem?
b. A chemist needs a compound cooled to less than 3cC. Determine the amount of time required for the compound to cool so that its temperature is less than 5°C.
Solve the equation. Write the smaller
answer first.
2
(x-6)²
= 36
x =
Α
x =
Previous Page
Next Page
Write a quadratic equation in
factored form that has solutions of x
=
2 and x = = -3/5
○ a) (x-2)(5x + 3) = 0
○ b) (x + 2)(3x-5) = 0
O
c) (x + 2)(5x -3) = 0
○ d) (x-2)(3x + 5) = 0
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.