Bundle: Refrigeration and Air Conditioning Technology, 8th + MindTap HVAC, 2 terms (12 months) Printed Access Card
8th Edition
ISBN: 9781337190336
Author: TOMCZYK
Publisher: CENGAGE L
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Textbook Question
Chapter 36, Problem 5RQ
What advantage does a thermostatic expansion valve have over a capillary tube?
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The state of stress at a point is σ = -4.00 kpsi, σy = 16.00 kpsi, σ = -14.00 kpsi, Try = 11.00 kpsi,
Tyz = 8.000 kpsi, and T = -14.00 kpsi.
Determine the principal stresses.
The principal normal stress σ₁ is determined to be [
The principal normal stress σ2 is determined to be [
The principal normal stress σ3 is determined to be
kpsi.
kpsi.
The principal shear stress 71/2 is determined to be [
The principal shear stress 7½ is determined to be [
The principal shear stress T₁/, is determined to be [
kpsi.
kpsi.
kpsi.
kpsi.
Repeat Problem 28, except using a shaft that is rotatingand transmitting a torque of 150 N * m from the left bearing to the middle of the shaft. Also, there is a profile keyseat at the middle under the load.
(I want to understand this problem)
Prob 2.
The material distorts into the dashed position
shown. Determine the average normal strains &x, Ey
and the shear strain Yxy at A, and the average
normal strain along line BE.
50 mm
B
200 mm
15 mm
30 mm
D
ΕΙ
50 mm
x
A
150 mm
F
Chapter 36 Solutions
Bundle: Refrigeration and Air Conditioning Technology, 8th + MindTap HVAC, 2 terms (12 months) Printed Access Card
Ch. 36 - True or False: Evaporative air-conditioning will...Ch. 36 - What are the advantages of using refrigerated...Ch. 36 - The four major components of an air-conditioning...Ch. 36 - Most compressors are cooled using the ___________.Ch. 36 - What advantage does a thermostatic expansion valve...Ch. 36 - What advantage does a capillary tube have over a...Ch. 36 - The ______expansion device ordinarily must use...Ch. 36 - The most popular refrigerant used in the past for...Ch. 36 - What are higher-efficiency refrigerant blends that...Ch. 36 - What refrigerant blend can be used in retrofit...
Ch. 36 - What types of heat are removed by the evaporator...Ch. 36 - The design boiling point for most evaporator coils...Ch. 36 - What are the three most common types of...Ch. 36 - The large interconnecting line between the indoor...Ch. 36 - The small interconnecting line between the indoor...Ch. 36 - The outside design temperatures in the summerin...Ch. 36 - The dew point temperature tells you how much...
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- 4: The boom AC is a 4-in. square steel tube with a wallthickness of 0.25 in. The boom is supported by the 0.5-in.-diameter pinat A, and the 0.375-in.-diameter cable BC. The working stresses are 25ksi for the cable, 18 ksi for the boom, and 13.6 ksi for shear in the pin.Neglect the weight of the boom.1. Calculate the maximum value of P (kips) based on boom compression and the maximum value of P (kips) based on tension in the cable.2. Calculate the maximum value of P (kips) based on shear in pin.arrow_forward3: A steel strut S serving as a brace for a boat hoist transmits a compressive force P = 54 kN to the deck of a pier as shown in Fig. STR-08. The strut has a hollow square cross section with a wall thickness t =12mm and the angle θ between the strut and the horizontal is 40°. A pin through the strut transmits the compressive force from the strut to two gusset plates G that are welded to the base plate B. Four anchor bolts fasten the base plate to the deck. The diameter of the pin is 20mm, the thickness of the gusset plates is 16mm, the thickness of the base plate is 8mm, and the diameter of the anchor bolts is 12mm. Disregard any friction between the base plate and the deck.1. Determine the shear stress in the pin, in MPa and the shear stress in the anchor bolts, in MPa.2. Determine the bearing stress in the strut holes, in MPa.arrow_forward1. In the figure, the beam, W410x67, with 9 mm web thicknesssubjects the girder, W530x109 with 12 mm web thickness to a shear load,P (kN). 2L – 90 mm × 90 mm × 6 mm with bolts frame the beam to thegirder.Given: S1 = S2 = S5 = 40 mm; S3 = 75 mm; S4 = 110 mmAllowable Stresses are as follows:Bolt shear stress, Fv = 125 MPaBolt bearing stress, Fp = 510 MPa1. Determine the allowable load, P (kN), based on the shearcapacity of the 4 – 25 mm diameter bolts (4 – d1) and calculate the allowable load, P (kN), based on bolt bearing stress on the web of the beam.2. If P = 450 kN, determine the minimum diameter (mm) of 4 – d1based on allowable bolt shear stress and bearing stress of thebeam web.arrow_forward
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